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3 years ago

Consider the function f(x) = {(6)". What is the value of the growth factor of the function?

Mathematics

1 answer:

Firlakuza [10]3 years ago

3 0

Answer:

Step-by-step explanation:

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The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit

wolverine [178]

Answer:

(a) $\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

$P(t)=\frac{240t-40t^2}{t^2+20}$

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

$P(t)=\frac{240t-40t^2}{t^2+20}$ using quotient rule.

$\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}$

Simplifying

$\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

$\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

$P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}$

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

$P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}$

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

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3 years ago

Which statements are true when you contrast multiplicative numerical patterns in the form and additive numerical patterns in the

Elina [12.6K]

Answer:

A. In an additive numerical pattern, the relationship between x and y values is y + x, but in a multiplicative pattern, the relationship is y × x.

Step-by-step explanation:

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3 years ago

Help mee pweaseeeeeee :)))

Ilya [14]

Answer: .4

Step-by-step explanation:

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3 years ago

What is 80.68 +79.56 equal

Sunny_sXe [5.5K]

<span>What is 80.68 +79.56 equal?
</span>80.68+79.56 =160.24

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What is the largest integer that is below square root of 7?

Butoxors [25]

Answer:

Step-by-step explanation:

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