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3 years ago

Find the cost for 812 kwhr of electricity at 7.3 cents per kwhr.

Mathematics

1 answer:

Over [174]3 years ago

5 0

812*0.073= the cost would be 59.276$. and I'm good with math if u need further help

Hope this helps

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Determine whether the following probability experiment represents a binomial experiment and explain the reason for your answer.

allochka39001 [22]

Answer:

No. See explanation below.

Step-by-step explanation:

Since the cards are being selected without replacement, every time we select a card, the probability varies (since there is one less card) and therefore, the probability doesn't remain the same for every trial and therefore, the probability of success changes for every trial.

It is because of this that this probability experiment doesn't represent a binomial experiment.

6 0

3 years ago

The quadratic formula of 3x^2+4x+5=0

-Dominant- [34]

Yea yeaaaaaaaaaaaaaaaaaa

6 0

3 years ago

Read 2 more answers

A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.

Finger [1]

Answer:

$P(X=1)$

And using the probability mass function we got:

$P(X=1) = (5C1) (0.25)^1 (1-0.25)^{5-1}= 0.396$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

For this cae that one buggy whip would be defective is $p = \frac{5}{20}=0.25$

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=5, p=0.25)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X=1)$

And using the probability mass function we got:

$P(X=1) = (5C1) (0.25)^1 (1-0.25)^{5-1}= 0.396$

3 0

3 years ago

a jar contains 5 blue marbles and 3 red marbles. suppose you choose a marble at random and do not replace it. then choose a seco

lina2011 [118]

$\mathbb P(R_1\cap R_2)=\mathbb P(R_2\mid R_1)\mathbb P(R_1)$

The probability of drawing a red marble on the first attempt is

$\mathbb P(R_1)=\dfrac{\dbinom31}{\dbinom51}=\dfrac35$

After the first marble is drawn, and we know it to be red, we're drawing the next marble from a pool with one less marble than before (i.e. conditioning on the event $R_1$ ). So

$\mathbb P(R_2\mid R_1)=\dfrac{\dbinom21}{\dbinom71}=\dfrac27$

And so

$\mathbb P(R_1\cap R_2)=\dfrac35\cdot\dfrac27=\dfrac6{35}$

4 0

3 years ago

13% of $99.99 = $26.00 O $25.98 O $13.00 O $12.99

vova2212 [387]

Answer:

12.99 or 13 rounded

Step-by-step explanation:

99.99/(.13)=12.9987

8 0

2 years ago