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3 years ago

Find the cost for 812 kwhr of electricity at 7.3 cents per kwhr.

Mathematics

1 answer:

Over [174]3 years ago

5 0

812*0.073= the cost would be 59.276$. and I'm good with math if u need further help

Hope this helps

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One angle of a triangle measures 65°. The other two angles are in a ratio of 3:20. What are the measures of those two angles?

Nataly_w [17]

Answer:

15° and 100°

Step-by-step explanation:

$65 + 3x + 20x = 180$

$23x = 115$

$x = 5$

3 × 5 = 15, 20 × 5 = 100. So the other two angles measure 15° and 100°.

3 0

2 years ago

Identify the solution <br> Answer choices<br> 1. 0,3<br> 2. 3, -2<br> 3. 4,2<br> 4 -2,3

Gennadij [26K]

Answer:

2) (3,-2)

Step-by-step explanation:

the solution is where the lines intersect. they intersect at one point because this function is linear. they intersect at the point (3,-2)

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3 years ago

Need help finding angles 1,2,3,4,5!!!!!

earnstyle [38]

Answer:

1. 18

2. 17

3. 26

4. 17

5. 18

4 0

3 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

3 years ago

Rep viuen

Keith_Richards [23]

Answer:

8 and -4

Step-by-step explanation:

8*-4=-32

8+(-4)=4

7 0

3 years ago