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fredd [130]
3 years ago
8

Helpp ill mark u as brain list​

Mathematics
1 answer:
kirill [66]3 years ago
7 0

Answer:

16.C

17.20

Step-by-step explanation:

16.Add 8+5=13

17.Add 12+8=20

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Need help with question
svetoff [14.1K]

Answer:

15 14/15

Step-by-step explanation:

8 + 7 = 15

1/3 + 3/5

5/15 + 9/15

14/15

15 + 14/15 = 15 14/15

5 0
2 years ago
F is between E and G. EF=3X, EG= 11x-2, FG= 5x+16. Find the value of the variable
Salsk061 [2.6K]

9514 1404 393

Answer:

  x = 6

Step-by-step explanation:

The sum of segments is used:

  EF +FG = EG

  3x +(5x +16) = 11x -2 . . . . substitute given expressions

  8x +18 = 11x . . . . . . . . add 2

  18 = 3x . . . . . . . . subtract 8x

  6 = x . . . . . . divide by 3

The value of the variable is 6.

__

<em>Check</em>

The segment lengths are ...

  EF = 3x = 3·6 = 18

  FG = 5x+16 = 5·6 +16 = 46

  EG = 11x -2 = 11·6 -2 = 64 = 18+46 . . . answer is correct

3 0
3 years ago
For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec
telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

4sin(x^2) = 0

sin(x^2) = 0

x^2 = n\pi where n = 0, 1, 2,3, 4, 5,...

x = \sqrt(n\pi)

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0

xcos(x^2) = 0

x = 0 or

cos(x^2) = 0

x^2 = \frac{\pi}{2} + n\pi where n = 0, 1, 2, 3

x = \sqrt{\pi(n+1/2)}

Since we are restricting x between 0 and 3 we can stop at n =  2

So our critical points are at

x = 1.25, y = f(1.25) = 4sin(1.25^2) = 4

x = 2.17 , y = f(2.17) = 4sin(2.17^2) = -4

x = 2.8, y = f(2.8) = 4sin(2.8^2) = 4

For the inflection point, we can take the 2nd derivative and set it to 0

f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0

cos(x^2) = 2x^2sin(x^2)

tan(x^2) = \frac{1}{2x^2}

We can solve this numerically to get the inflection points are at

x = 0.81, y = f(0.81) = 4sin(0.81^2) = 2.44

x = 1.81, y = f(1.81) = 4sin(1.81^2) = -0.54

x = 2.52, y = f(2.52) = 4sin(2.52^2) = 0.27

3 0
3 years ago
Please find the area<br> 420ft2<br><br> 210ft2
Minchanka [31]

Answer:

Area= L×B

Area=420ft²×210ft²

Area=88200ft²

7 0
3 years ago
A company makes paper labels for paint cans. As shown below, each can is in the shape of a cylinder
sineoko [7]

The company needs 41 labels on average, each minute.

<h3>What is the circumference of a circle?</h3>

The perimeter of a circle (circumference): 2 π radius

Replacing with the values given:

C = 2 (3.14) 2 = 12.56 cm

So, the area of one label is:

Area of a rectangle: length x width = 12.56 x 7 = 87.92 cm sq.

Now, the number of label be n

87.92 x n = 3612.64 cm2

n = 3612.64 / 87.92

n = 41.09

Hence, The company needs 41 labels on average, each minute.

Learn more about circumference;

brainly.com/question/4268218

#SPJ1

6 0
2 years ago
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