Answer:
B)
Step-by-step explanation:
Count up every line to B, (6)
Count over to every line to C, (6)
Add the total number of movements,
12
Hope this helps! Have a great day :)
-wfz
27 is 54% of 50! You can set up fractions (proportions) as 27/50 = blank/100!
Well how do you get to 50 to 100? You multiply by 2! And whatever you do to the bottom you must do to the top! So 27 times 2 is 54!
Answer:
W= 5.744
Step-by-step explanation:
given that a grocery store produce manager is told by a wholesaler that the apples in a large shipment have a mean weight of 6 ounces and a standard deviation of 1.4 ounces
Sample size n= 49
Margin of error = 0.10 (10% risk )
Let us assume X no of apples having mean weight of 6 oz is N(6,1.4)
Then sample mean will be normal with (6, 1.4/7) = (6,0.2)
(Because sample mean follows normal with std error as std dev /sqrt of sample size)
Now required probability <0.10
i.e.![P(\bar X](https://tex.z-dn.net/?f=P%28%5Cbar%20X%20%3CW%29%20%3C0.10)
Since x bar is normal we find z score for
![P(Z](https://tex.z-dn.net/?f=P%28Z%3Cz%29%20%3C%200.10%5C%5C)
From std normal distribution table we find that z = 1.28
Corresponding X score =
![W= 6-0.2*1.28\\W= 6-0.256 = 5.744](https://tex.z-dn.net/?f=W%3D%206-0.2%2A1.28%5C%5CW%3D%206-0.256%20%3D%205.744)
Answer:
6 feet in the distance
Step-by-step explanation:
There are
![\dbinom62](https://tex.z-dn.net/?f=%5Cdbinom62)
ways of selecting two of the six blocks at random. The probability that one of them contains an error is
![\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cdbinom11%5Cdbinom51%7D%7B%5Cdbinom62%7D%3D%5Cdfrac5%7B15%7D%3D%5Cdfrac13)
So
![X](https://tex.z-dn.net/?f=X)
has probability mass function
![f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}](https://tex.z-dn.net/?f=f_X%28x%29%3D%5Cbegin%7Bcases%7D%5Cdfrac13%26%5Ctext%7Bfor%20%7Dx%3D1%5C%5C%5C%5C%5Cdfrac23%26%5Ctext%7Bfor%20%7Dx%3D0%5Cend%7Bcases%7D)
These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then