We have the following information:
first urn: 6 green balls and 3 red ones
total: 6 + 3 = 9
second urn: 3 green, 3 white and 3 red
total: 3 + 3 + 3 = 9
third urn: 6 green, 1 white and 2 red
total: 6 + 1 + 2 = 9
a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.
b) probability of drawing a green, red and white ball.
first urn:
green = 6/9 = 66.66%
red = 3/9 = 33.33%
white = 0/9 = 0%
second urn:
green = 3/9 = 33.33%
red = 3/9 = 33.33%
white = 3/9 = 33.33%
third urn:
green = 6/9 = 66.66%
red = 2/9 = 22.22%
white = 1/9 = 11.11%
c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%
d) without a green ball, the third ballot box would look like this:
5 green balls, 2 red balls and 1 white ball, with a total of 8.
The probability of drawing would be:
green = 5/8 = 62.5%
red = 2/8 = 25%
white = 1/8 = 12.5%
Answer:
-10
Step-by-step explanation:
the upper right is the same (105°), therefore the left 75°
now you have 180 = 75 + x + 115
therefore: -10
Answer:
164 is the answer♀️
Step-by-step explanation:
........ also if its correct i need the brainliest
Answer:
158 m²
Step-by-step explanation:
I made this into 3 rectangles.
Figure 1:
9•8=72
The 9 is from the 13 m side, but I've taken 4 m off from the overlapping square.
Figure 2:
6•7=42
The 7 is from the 10 m side, but I've taken 4m off from the overlapping square again.
Remaining Area:
If you extend the lines into figures 1 and 2 from the top left corner and bottom right corner vertically, you will get a rectangle that is (11 m) x (4 m). This is not yet accounted for.
11•4=44
Add together: 72 + 42 + 44 = <u>158</u>
*Note: You could also find the area of the squares a much easier way by subtracting the overlapping part after finding the area of both figures , but this is how I did it*
