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jarptica [38.1K]
3 years ago
15

simba travel agency arranged trips for climbing mount kilimanjaro. for each trip, they charge an initial fee of 100$ in addition

to a constant fee for each veriticle meter climbed. for instance, the total fee for climbing to the shira volcanic cone, which is 3000 meters above the base of the mountain is 400$. let y represent the total fee in dollars of a trip where they climbed x vertical meters.
Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0
Yesterday was a great
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Read 2 more answers
Please help and explain with these 2 math questions!!!!!!
Volgvan

1)  -10x+y=4

Now, you should substitute x in every situation.

* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>

<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>

<u />*x=0 => -10*0+y=4... <u>y=4</u>

<u />* x=1 =>  -10*1+y=4... -10+y=4... <u>y=14</u>

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<u>2)</u> -5x-1=y

For example: x=0

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<u>
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6 0
3 years ago
Can someone help me with this? (screenshot of problem attached)
mote1985 [20]

Answer:

Step-by-step explanation:

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7 0
3 years ago
A company’s profit in dollars is modeled by the equation p(x) = –0.5x2 + 100x, where x represents the number of units sold.
serg [7]

Answers:

a. The company needs to sell 100 units to reach the maxmum profit.

b. The company's maximum profit is $5,000.

Solution:

a. How many unit does the company need to sell to reach the maximum profit?

p(x)=-0.5x^2+100x

This is a quadratic equation, and its graph is a parabola vertical (because the veriable "x" is square). Comparing with the general form:

p(x)=ax^2+bx+c; a=-0.5, b=100, c=0

a=-0.5<0 (negative), then the parabola opens downward, and it has a maximimun value (maximum profit) at its vertex.

We can find the abscissa of the vertex (units that the company needs to sell to reach the maximum profit using the following formula:

x=-b/(2a)

Replacing b by 100 and a by -0.5 in the formula above:

x=-100/[2(-0.5)]

x=-100/(-1)

x=100

The company needs to sell 100 units to reach the maximum profit.


b. What's the company's maximum profit?  

To determine the maximum profit we substitute the value of "x" obrained in part "a" in the quadratic equation:

x=100→p(100)=-0.5(100)^2+100(100)

p(100)=-0.5(10,000)+10,000

p(100)=-5,000+10,000

p(100)=5,000

The company's maximum profit is $5,000.

6 0
3 years ago
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