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Natasha_Volkova [10]
3 years ago
15

Two adjacent natural frequencies of an organ pipe are AMT determined to be 550 Hz and 650 Hz. Calculate (a) the M fundamental fr

equency and (b) the length of this pipe.
Physics
1 answer:
allochka39001 [22]3 years ago
4 0

Answer:

The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.

Explanation:

Given that,

Frequency f = 550 Hz

Frequency f' = 650 Hz

We know that,

AMT pipe is open pipe.

(b). We need to calculate the length of the pipe

Using formula of organ pipe

f=\dfrac{nv}{2L}

For 550 Hz,

550=\dfrac{n\times340}{2L}...(I)

For 650 Hz,

650=\dfrac{(n+1)\times340}{2L}...(II)

From equation (I) and (II)

550-650=\dfrac{340}{2L}-\dfrac{340}{L}

L=\dfrac{340}{2\times100}

L=1.7\ m

(a). We need to calculate the fundamental frequency for n = 1

Using formula of  fundamental frequency

=f=\dfrac{n\lambda}{2L}

put the value of L

f=\dfrac{1\times340}{2\times1.7}

f=100\ Hz

Hence, The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.

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