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belka [17]
2 years ago
8

Which is the correct equation for the force applied by a spring?

Physics
1 answer:
slava [35]2 years ago
3 0

Answer:

B. F = -k*x

Explanation:

The force of a spring can be easily calculated using Hooke's law which tells us that the force applied on a spring is equal to the product of the constant of a spring by the compressed or stretched distance of the spring.

That is:

F = k*x

k = spring constant [N/m]

x = distance [m]

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A bus is moving and has 500000 joules of kinetic energy. The brakes are applied and the bus stops. How much work is needed to st
Bad White [126]
For the work-energy theorem, the work needed to stop the bus is equal to its variation of kinetic energy:
W=K_f - K_i
where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus

Since the bus comes at rest, its final kinetic energy is zero: K_f = 0, so the work done by the brakes to stop the bus is
W=-K_i = -500000 J
And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.
8 0
2 years ago
A 3.91 kg cart is moving at 5.7 m/s when it collides with a 4 kg cart which was at rest. They collide and stick together.
Nesterboy [21]

Answer:

<em>The velocity after the collision is 2.82 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of two bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

The common velocity after this situation is:

\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}

There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.

After the collision, both cars stick together. Let's compute the common speed after that:

\displaystyle v'=\frac{3.91*5.7+4*0}{3.91+4}

\displaystyle v'=\frac{22.287}{7.91}

\boxed{v' = 2.82\ m/s}

The velocity after the collision is 2.82 m/s

6 0
2 years ago
Which of the following is not an example of work, according to the scientific definition
bogdanovich [222]

Leaning against a brick wall.

All the others use scientific forces of work.

-Steel jelly.

6 0
2 years ago
Read 2 more answers
Light passes through a pair of narrow slits with a 0.67-mm separation. It is found that the fourth bright fringe makes an angle
babunello [35]

Answer:

The wavelength of the light is 555 nm.

Explanation:

according to Bragg's law..

n×λ = d×sin(θ)

n is the fringe number

λ is the wavelength of the light

d is the slit separation

θ is the angle the light makes with the normal at the fringe.

7 0
3 years ago
in which type of wave are vibrations at right angles to the direction in which the wave is travelling​
Pani-rosa [81]

Answer:

longitudinal waves have those properties

7 0
2 years ago
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