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kirill115 [55]
3 years ago
7

PLS I NEED HELP I ONLY HAVE 15 MINS I BEG YOU PLEASE!! :(

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0

Answer:

by 28% or 280%

not completely sure

Step-by-step explanation:

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−\frac{7}{10} ÷\frac{2}{5}
bazaltina [42]
$$ −\frac{7}{10} \div\frac{2}{5}= \frac{-7}{4} $$ . totally answer. I hope helping with this answer
3 0
3 years ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
mamaluj [8]

Answer:

Systolic variation coefficient (CVS) = 0.1446 = 14.46%

Diastolic variation coefficient (CVD) =  0.1789 = 17.89%

The variation, with respect to the mean, of the systolic pressure sample is slightly less than the variation of the Diastolic pressures.

Step-by-step explanation:

Systolic Mean (MS) = 127.8

Diastolic Mean (MD) = 73.5

Standard Deviation Systolic (sdS) = 18,486

Standard Deviation Diastolic (sdD) = 13.1508

The coefficient of variation is defined by:

Systolic variation coefficient (CVS) = sdS / MS = 18.486 / 127.8 = 0.1446 = 14.46%

Diastolic variation coefficient (CVD) = sdD / MD = 13.1508 / 73.5 = 0.1789 = 17.89%

Then, it can be concluded that the variation, with respect to the mean, of the systolic pressure sample is slightly less than the variation of the Diastolic pressures.

8 0
3 years ago
Someone help me plzzz:((((
mash [69]

Step-by-step explanation:

OI= 3.2 cm (same as OH)

To find GI, use Pythagoras Theorem (a²+b²= c²)

6.8²+3.2²= 56.48

√56.48= 7.5 cm

hope it helps! please mark me brainliest

thank you! have a good day ahead

if u follow me, i will follow u back

3 0
3 years ago
Read 2 more answers
Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-
AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

a)

\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\

So, this integral is convergent.

b)

\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\

So, this integral is divergent.

c)

\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\

So, this integral is divergent.

4 0
3 years ago
Did I do this right?<br> In △JKL, ​ LO=104 cm ​.<br><br><br><br> What is the length of NO¯¯¯¯¯¯?
Marat540 [252]
Yes, The correct answer is 
NO =  52 cm
8 0
3 years ago
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