Question

What is an equation of the line that is parallel to y=9-5x and passes through (0, 8)?

Answer 1

The slope of the given line is the x-coefficient, -5. Then, in point-slope form an equation for the line you want is
  y - 8 = -5(x - 0)

This simplifies to
  y = 8 -5x

Answer 2

Answer:

Step-by-step explanation:

The general equation of  a line is $y=mx+b$ where m is the slope and b the y intercept.

We have the equation of a line: y=-5x+9. Where $m_1=-5$

And we have to find $y=m_2x+b_2$

Two lines are parallel if the slopes are the same, this means $m_1=m_2$

Then $m_2=-5$

$y=-5x+b_2$

We have to find the y intercept. We now that the line passes through (0,8) then we have to replace this point in $y=-5x+b_2$

$y=-5x+b_2\\8=-5.(0)+b_2\\8=b_2$

Then the equation of the line that is parallel to y=9-5x and passes through (0, 8) is $y=-5x+8$

In the graph of the lines where y=-5x+9 is pink and y=-5x+8 is green, you can see that they are parallels: