Answer:
3/2 is the answer
Step-by-step explanation:
The answer is b I hope this helps
Answer:
B. 14x^3+39x^2+18x+20
Step-by-step explanation:
Given polynomials are:
![(7x^2+2x+4)(2x+5)\\For\ product\\(2x+5)(7x^2+2x+4)\\= 2x(7x^2+2x+4)+5(7x^2+2x+4)\\= 14x^3+4x^2+8x+35x^2+10x+20\\Combining\ alike\ terms\\= 14x^3+4x^2+35x^2+8x+10x+20\\=14x^3+39x^2+18x+20](https://tex.z-dn.net/?f=%287x%5E2%2B2x%2B4%29%282x%2B5%29%5C%5CFor%5C%20product%5C%5C%282x%2B5%29%287x%5E2%2B2x%2B4%29%5C%5C%3D%202x%287x%5E2%2B2x%2B4%29%2B5%287x%5E2%2B2x%2B4%29%5C%5C%3D%2014x%5E3%2B4x%5E2%2B8x%2B35x%5E2%2B10x%2B20%5C%5CCombining%5C%20alike%5C%20terms%5C%5C%3D%2014x%5E3%2B4x%5E2%2B35x%5E2%2B8x%2B10x%2B20%5C%5C%3D14x%5E3%2B39x%5E2%2B18x%2B20)
The product of given polynomials is:
14x^3+39x^2+18x+20
Hence, Option B is correct ..
Answer:
Using the formula:
![A=P+I](https://tex.z-dn.net/?f=A%3DP%2BI)
where
A is the total amount
P is the principal
I is the Simple Interest
As per the statement:
Principal(P) = 5300 rupees.
rate of interest(r) = 6.5% = 0.065
Total amount(A) = 6678 rupees.
Then using above formula we have;
![6678 = 5300+I](https://tex.z-dn.net/?f=6678%20%3D%205300%2BI)
Subtract 5300 both sides we get;
![1378 = I](https://tex.z-dn.net/?f=1378%20%3D%20I)
or
![I = \$1378](https://tex.z-dn.net/?f=I%20%3D%20%5C%241378)
We have to find the time period.
Using formula of Simple interest:
![I = Prt](https://tex.z-dn.net/?f=I%20%3D%20Prt)
where r is the rate of interest (in decimal)
here, r = 6.5% = 0.065
Substitute the given values top find t:
![1378 = 5300 \cdot 0.065 \cdot t](https://tex.z-dn.net/?f=1378%20%3D%205300%20%5Ccdot%200.065%20%5Ccdot%20t)
⇒![1378 = 344.5t](https://tex.z-dn.net/?f=1378%20%3D%20344.5t)
Divide both sides by 344.5 we have;
![4 = t](https://tex.z-dn.net/?f=4%20%20%3D%20t)
Therefore, the time period t in years is 4 years