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4 years ago

ANSWER BOTH thanksss

Mathematics

2 answers:

mamaluj [8]4 years ago

8 0

-400 and -95. i hope i helped

NNADVOKAT [17]4 years ago

3 0

Answer:

x=-400

x=-95

Step-by-step explanation:

They are negative because a negative times a negative is a positive.

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To solve this system of equations by elimination, what operation could be used to eliminate the y-variable and find the value of

artcher [175]

Answer:

Option B is correct.

add 4 times the second equation to 3 times the first equation

Step-by-step explanation:

Given the system of equation:

$2x - 4y = 6$ ......[1]

$-3x + 3y =12$ .....[2]

Multiply equation [1] by 3 we get;

$3(2x-4y) = 3 \cdot 6$

Using distributive property; $a\cdot (b+c) = a\cdot b+ a\cdot c$

6x - 12y = 18 .......[3]

Multiply equation [2] by 4 we get;

$4(-3x+3y) = 4 \cdot 12$

Using distributive property we get;

-12x + 12y = 48 ......[4]

Add equation [3] and [4] to eliminate y and solve for x;

(6x -12y) + ( -12x +12y ) = 18 + 48

6x - 12y -12x + 12y = 66

Combine like terms;

6x - 12x = 66

-6x = 66

Simplify:

x = -11

Therefore, the operation which could be used to eliminate the y-variable and find the value of x is;

add 4 times the second equation to 3 times the first equation.

4 0

3 years ago

Read 2 more answers

A coin is tossed 10 times. True or false, and explain: (a) The chance of getting 10 heads in a row is 1/1,024. (b) Given that th

Llana [10]

Answer:

a and b both are true.

Step-by-step explanation:

Given : A coin is tossed 10 times.

To find : True or false, and explain ?

Solution :

(a) The chance of getting 10 heads in a row is $\frac{1}{1024}$

Coin has two face head and tail.

The probability of getting head is $P(H)=\frac{1}{2}$

The probability of getting 10 heads in a row is

$P=(P(H))^{10}$

$P=(\frac{1}{2})^{10}$

$P=\frac{1}{1024}$

The chance of getting 10 heads in a row is $\frac{1}{1024}$ is true.

(b) Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is $\frac{1}{2}$ .

The probability of getting 10 heads in a row is $P_1=(\frac{1}{2})^{10}$

The probability of getting 9 tosses were heads is $P_2=(\frac{1}{2})^{9}$

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is given by,

$P=\frac{P_1}{P_2}$

$P=\frac{(\frac{1}{2})^{10}}{(\frac{1}{2})^{9}}$

$P=(\frac{1}{2})^{10-9}$

$P=\frac{1}{2}$

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is $\frac{1}{2}$ is true.

3 0

4 years ago

I need help anyone knows the answers kindly plz help

sergij07 [2.7K]

Yeah put 6 on the 5-223 because it is -6 5 don’t answer

5 0

3 years ago

Find the distance from G to S.

OLEGan [10]

The distance formula is the square root of (x1-x2)^2+ (y1-y2)^2

So it would be square root [ (-2-3)^2 + (6-(-2))^2]
So it would be square root(25+64)
Square root(89)= 9.433

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3 years ago

Starting with the formula for the difference of cubes, which pair of steps can be used to show that the expressions are

vagabundo [1.1K]

C hope it helps ¯\_(ツ)_/¯

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3 years ago

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