Answer:
The equation of tangent plane to the hyperboloid
.
Step-by-step explanation:
Given
The equation of ellipsoid

The equation of tangent plane at the point 
( Given)
The equation of hyperboloid

F(x,y,z)=


The equation of tangent plane at point 

The equation of tangent plane to the hyperboloid

The equation of tangent plane

Hence, the required equation of tangent plane to the hyperboloid

I'm pretty sure that this is a trick question, the answer is 61%.
You know how Soh Cah Toa applies to right triangles; you can assign the adjacent side = 4 and hypotenuse = 7
CosФ = (adjacent) / (hypotenuse)
Then with the Pythagorean theorem
4² + b² = 7²
16 + b² = 49
b² = 49 - 16
b² = 33
b = √(33)
So "b" is the opposite side.
SinФ = (opposite) / (hypotenuse) = √(33)/7
TanФ = (opposite) / (adjacent) = √(33)/4
I would be B. because from 4 to 20 is times 5 so you just divide 45 by 5 and you get 9.
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