Answer:
Part 1) The exponential function is equal to 
Part 2) The population in 2010 was 
Step-by-step explanation:
Part 1) Write an exponential decay function that models this situation
we know that
In this problem we have a exponential function of the form
where
y ----> the fish population of Lake Collins since 2004
x ----> the time in years
a is the initial value
b is the base
we have
substitute
----> exponential function that represent this scenario
Part 2) Find the population in 2010
we have
so
For 
substitute
Problem 3
The constant term is 290. This is the term that stays the same no matter what the value of 'a' happens to be. Contrast this with the variable term 2.50a which changes if 'a' changes (hence the name "variable" for "vary" or "change")
If Mike sold 0 accessories, then a = 0 and the expression would be
2.50*a + 290 = 2.50*0 + 290 = 290
Selling 0 accessories leads to $290. This is the amount he is guaranteed with the 2.50a portion being additional money to motivate him to sell more.
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Answer: Choice (3) 290, amount he is guaranteed
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Problem 4
Plug y = 0 into the equation. Solve for x
9x - 14y = -3
9x - 14*0 = -3 .... replace y with 0
9x - 0 = -3
9x = -3
9x/9 = -3/9 ... divide both sides by 9
x = -3/9
x = -1/3
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Answer: Choice (3) which is -1/3
Answer: 11 units
Step-by-step explanation: Just took it on edg.
Answer:
the third one
Step-by-step explanation:
If $.72 per 1lb, then $x per 2.7lb, by using proportional property:
.72/1 = x/2.7 cross multiply
x = (.72)*(2.7) = $1.94
