The total number of seats in the theater is 600 seats, if the students filled up 570 seats, which was 95% of the total number of seats in the theater.
Step-by-step explanation:
The given is,
Seats filled by students are 570 seats
Which is 95% of the total number of seats in the theater
Step: 1
Let, x - Total number of seats available in theater
Percentage of seats filled, y= 95%
Seats filled by students = 570
Formula to calculate total number of seats in theater,
95% of seats
570 = 
x = 
= 600
x = 600 seats
Step: 2
Check for solution,
5% of seats 
= (0.05 × 600)
= 30 seats
Total no. of seats = 5% of seats + 95% of seats
= 30 + 570
600 = 600
Result:
The total number of seats in the theater is 600 seats.
Awnser:69
I had this question a few minutes ago, that’s funny
The slope of a horizontal line will have a value equal to 0:
m=0
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
We have a point ( E(3,-4) ) and the slope of this line (m=0); therefore:y
y+4=0(x-3=
y+4=0
y=-4
Answer: the equation for the horizontal line that contains the point E, would be:
y=-4
Substitute
, so that

Then the resulting ODE in
is separable, with

On the left, we can split into partial fractions:

Integrating both sides gives




Now solve for
:

