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GalinKa [24]
2 years ago
14

During geography class students listed the number of the states they had visited.the responses were 12,9,17,7,5,4,2,1,8,5

Mathematics
2 answers:
Darya [45]2 years ago
7 0

Answer:

C

Step-by-step explanation:

I think not %100 sure but I hope this helps <3

jeyben [28]2 years ago
4 0

Answer:

7

Step-by-step explanation:

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Marla draws a diagonal in a rhombus to form two triangles. What term can she use to classify each triangle?
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C

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I really need helpppppp<br><br> I’m confused
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Add 35+ 72.5=107.5 that should give you your answer for c and the answer for d is acute because the triangle would have to be 360 to be Obtused and it's not a right triangle because you don't have a 90 degree angle
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You are ordering shirts for the math club at your school. Short-sleeved shirts cost $10 each. Long-sleeved shirts cost $12 each.
Taya2010 [7]

Answer:

10x+12y=300

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Is the triangle with the given dimensions a right triangle? If so, which angle is the right angle? AB =10, BC= 8, CA= 5
ExtremeBDS [4]
No it's not a right triangle.
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3 years ago
Line segment 19 units long running from (x,0) ti (0, y) show the area of the triangle enclosed by the segment is largest when x=
Debora [2.8K]
The area of the triangle is

A = (xy)/2

Also,

sqrt(x^2 + y^2) = 19

We solve this for y.

x^2 + y^2 = 361

y^2 = 361 - x^2

y = sqrt(361 - x^2)

Now we substitute this expression for y in the area equation.

A = (1/2)(x)(sqrt(361 - x^2))

A = (1/2)(x)(361 - x^2)^(1/2)

We take the derivative of A with respect to x.

dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]

dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]

Now we set the derivative equal to zero.

(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0

-2x^2 + 361 = 0

-2x^2 = -361

2x^2 = 361

x^2 = 361/2

x = 19/sqrt(2)

x^2 + y^2 = 361

(19/sqrt(2))^2 + y^2 = 361

361/2 + y^2 = 361

y^2 = 361/2

y = 19/sqrt(2)

We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
3 0
3 years ago
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