Answer:
81.85%
Step-by-step explanation:
Given :
The average summer temperature in Anchorage is 69°F.
The daily temperature is normally distributed with a standard deviation of 7°F .
To Find:What percentage of the time would the temperature be between 55°F and 76°F?
Solution:
Mean = 
Standard deviation = 
Formula : 
Now At x = 55


At x = 76


Now to find P(55<z<76)
P(2<z<-1)=P(z<2)-P(z>-1)
Using z table :
P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185
Now percentage of the time would the temperature be between 55°F and 76°F = 
Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.
Answer:
.375
Step-by-step explanation:
((3/4)/1)/2 = 0.375
Hope it helps
Answer:x= 0.5,−3
Step-by-step explanation:
Answer:
x=-6
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(6-2)/(-6-(-6))
m=4/(-6+6)
m=4/0
undefined
x=-6
Answer:jusk click that the answer is there i hope its correct correct me if im wrong
Step-by-step explanation: