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romanna [79]
3 years ago
7

2. Samuel used clay to make a diorama of the pyramids in Ancient Egypt. He made two triangular pyramids and three rectangular py

ramids. How much clay did he use to create all the pyramids?
Mathematics
1 answer:
zalisa [80]3 years ago
5 0

Answer:

124.16 cubic meter of clay will be used to create all the pyramids

Step-by-step explanation:

The remaining part of the question is given in the attached file

Solution

The total clay used is equal to the sum of volumes of two triangular and three rectangular pyramids.

For Rectangular Pyramid,

Volume of three rectangular pyramids

3 * \frac{BH}{3} = BH

Substituting the given values in above equation, we get -

15.5 * 5 = 77.5 cubic centimeter

For triangular Pyramid,

Volume of two  triangular pyramids

2 * \frac{BH}{3}\\2 * \frac{10 * 7}{3}

46.67  cubic centimeter

Total clay used = Volume of 3 rectangular pyramid + volume of 2 triangular pyramid = 77.7 + 46.67 = 124.16 Cubic centimeter

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Find the surface area of the triangular prism (above) using its net (below).
r-ruslan [8.4K]

Answer:

96 square units

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached photo.

My answer:

  • The length of the large rectangle is: 5
  • The width of the large rectangle is: 7

=> Area of the large rectangle = length × width  = 7*5 = 35 square units

  • The length of the middle rectangle is: 7
  • The width of the middle rectangle is: 4

=> Area of the middle rectangle = length × width  = 7*4 = 28 square units

  • The length of the small rectangle is: 7
  • The width of the small rectangle is: 3            

=> Area of the small rectangle = length × width  = 7*3 = 21 square units

Area of top and the bottom triangles =2* \frac{1}{2}bh  = 4*3 =12  

Total surface area = 35 + 28 + 21 + 12 = 96 square units

3 0
3 years ago
Read 2 more answers
A rectangle sand box has a length of 5 and 1/3 feet and a width of 3 and 3/4 feet. What is the perimeter?
Varvara68 [4.7K]

Answer:

Perimeter of rectangle = ⇒ 18\frac{1}{6} feet

Step-by-step explanation:

Given:

Length of a rectangular sand box = 5\frac{1}{3}\ feet

Width of the box = 3\frac{3}{4}\ feet

Perimeter of a rectangle = 2(l+w)

where l represents length of rectangle and w represents width of the rectangle.

Substituting values given for length and width.

Perimeter of sand box = 2(5\frac{1}{3}+3\frac{3}{4})\ feet

Simplifying by adding fractions:

⇒  2(5+3+\frac{1}{3}+\frac{3}{4})\ feet (Adding whole numbers and fractions separately)

⇒  2(8+\frac{1}{3}+\frac{3}{4}) feet

Whole number 8 can be written as \frac{8}{1}

⇒  2(\frac{8}{1}+\frac{1}{3}+\frac{3}{4}) feet

To add fractions we take LCD for the denominators 3,4,1.

LCD for 3 and 4 = 12 as its the least common multiple of 3,4,1.

Making denominators =12 by multiplying numerator an denominator with the corresponding numbers

⇒  2(\frac{8\times 12}{1\times 12}+\frac{1\times 4}{3\times 4}+\frac{3\times 3}{4\times 3}) feet

⇒  2(\frac{96}{12}+\frac{4}{12}+\frac{9}{12}) feet

Then we simply add numerators.

⇒  2(\frac{96+4+9}{12}) feet

⇒  2(\frac{109}{12}) feet

⇒  2\times \frac{109}{12} feet

⇒  \frac{218}{12} feet

Writing fraction as a mixed number by dividing 218 by 12 and writing quotient as whole number and remainder as numerator with divisor as denominator.

⇒ 18\frac{2}{12} feet

Simplifying fractions to simplest form.

⇒ 18\frac{1}{6} feet

Perimeter =⇒ 18\frac{1}{6} feet  (Answer)

5 0
3 years ago
What are the x-intercepts of the quadratic function?
maw [93]
To find the x intercept set y = 0

x^2 + x  - 2 =0 

(x+2)(x-1) = 0

x = -2 , x = 1


8 0
3 years ago
Read 2 more answers
Which values are solutions to the inequality below? . . Check all that apply.. . x2 > 49. .
Marianna [84]
   
x^2 \ \textgreater \  49 \\  \\ 
x_{1,2} =  \pm \sqrt{49}  = \pm 7 \\  \\ 
\boxed{x \in (-\infty, ~-7)\bigcup (7,~ +\infty) }



6 0
3 years ago
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I think it’s 2 over 1 but I’m not sure??
solmaris [256]

Answer:

it is 2/1

Step-by-step explanation:

4 0
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