Answer:
Strain Presence of Lactose Absence of Lactose
(+) (-)
For the wild type case, the lacZ gene product will be expressed in the presence of lactose only.
(-) (-)
Because of the super repressor, transcription will not take place regardless of the presence of lactose.
(+) (+)
The constitutive operator will allow for transcription to occur, whether or not lactose is present.
(+) (+)
The repressor is non-functional, transcription will occur with or without presence of lactose.
(+) (+)
The super repressor will not be able to stop transcription as it cannot bind to the constitutive operator.
(-) (-)
The promoter is non-functional, transcription will not start and hence, not gene product formed.
(-) (with glucose present) (-)
E. coli will not metabolize lactose in the present of glucose, since glucose is the preferred source of nutrition.
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Answer:
C. I and II only
Explanation:
i took the test and got it right
Not all intercellular signals require transduction. For example, a lipid-soluble signal is one of the types of signals which can be processed without transduction.
Lipid signaling can be broadly defined or refers to a kind of biological signaling event which involves a lipid messenger that binds a target protein, such as a kinase, receptor, or phosphatase, that judges the effects of these lipids on the specific cellular responses.
Therefore, a lipid-soluble signal does not require signal transduction because a lipid-soluble signal can easily dissolve in the blood and can easily flow or transmit throughout the body and organs. They don't require any series of molecular events for transmission.
Learn more about lipid-soluble signal here
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<span>Much like a cell, a virus is able to
Answer: </span>
<span> change over time.
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Answer:
it's equal to mass of CaO plus the mass of CO2 by law of conservation.