Question

A chemist prepares a solution of silver(I) nitrate AgNO3 by measuring out ×4.7102μmol of silver(I) nitrate into a 450.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /mmolL of the chemist's silver(I) nitrate solution. Be sure your answer has the correc

Answer 1

The concentration in /mmolL of the chemist's silver(I) nitrate solution is 0.01047 mmoles/litre.

Explanation:

Data given:

Number of moles of AgNO3 in micro mole 4.7102micromol.

The concentration is supposed to be in mmol so the micromole will be converted to milimole.

So, 1 micromole = 0.001 millimole

hence, 4.712micromole will be 0.004712 millimole.

Volume is given as 450ml which is converted into L

to convert ml into L it is divided by 1000

so 0.45 L is the volume.

Molarity or concerntration is calculated by the formula,

molarity = $\frac{number of moles}{volume in litres}$  

putting the values in the formula:

molarity = $\frac{0.0047103}{0.45}$

              = 0.01047 mmoles/litre is the molarity of AgNO3 solution in 450 ml of solution.