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Solnce55 [7]
3 years ago
10

Ms. Block's students are studying chemical reactions as well as the law of conservation of matter. A classic reaction occurs whe

n a metal is added to hydrochloric acid. Miguel and Kai are about to add 30g of hydrochloric acid (HCl) to 30g of magnesium (Mg) in a large test tube. How could you adapt the boys experimental design so they would definitely be testing the law of conservation of matter?
A) The boys could use less hydrochloric acid to produce less gas bubbles.
B) The boys should use a container, such as a flask, that is larger than a test tube.
C) The boys could cover the end of the test tube with a balloon to capture the escaping gas.
D) One of the boys could place a hand over the end of the test tube to create a closed system.
Chemistry
2 answers:
goblinko [34]3 years ago
4 0

The answer is; C

Conservation of matter in a reaction means that the mass of matter in the products is equal to the mass of the reactants. Energy/matter cannot be created or destroyed but converted from one form to another.

An expanding balloon with the increased evolution of gas is a good visible practical sign in the experiment on the conservation of matter in the reaction. As the magnesium disappears with an increased input of hydrochloric acid, the balloon gets bigger showing that more hydrogen is evolved from the reaction;

2HCL + Mg  MgCl2 + H2  


Marat540 [252]3 years ago
3 0

Answer:

A

Explanation:

out of  A. 8g of hydrogen gas escaped from the test tube.

               B)8g of magnesium disappeared during the reaction.

        C) Miguel and Kai were not very proficient at using the beam balance.

               D) 8g of the mass produced the heat the boys felt at the end of the experiment.

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The answer is- SF_{6} is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.

Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.

Determine the molecular geometry of SF_{6}.

  • Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
  • According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
  • Now, calculate the total number of valence electrons in SF_{6}.

Valence\ electrons\ in\ SF_{6}= Valence\ electrons\ in\ S +\ 6(Valence\ electrons\ in\ F)

Valence electrons of S = 6

Valence electrons of F = 7

Thus, the valence electrons in SF_{6} are-

Valence\ number\ of\ electrons\ in\ SF_{6} = (6) + 6(7) = 48\ electrons.

  • The Lewis structure of SF_{6} is - (Image attached).
  • In the structure, the number of atoms bonded to central atom (S) = 6.
  • Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
  • Electronic geometry in case of 6 bond pairs is octahedral.
  • Molecular geometry us also octahedral with bond angles 90°.
  • Central atom is sp3d2 hybridised.
  • SF_{6} is a non-polar molecule.

To learn more about Lewis structures visit:

brainly.com/question/12307841?referrer=searchResults

#SPJ4

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