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Tcecarenko [31]
4 years ago
13

A company sells a natural medicine with plant ingredients to help treat dementia, a disease in which people have a hard time rem

embering things. The natural ingredients in the medicine are most likely from which type of plant?
-gnetophyte
-conifer
-ginkgo
-cycad
Chemistry
2 answers:
sammy [17]4 years ago
5 0
I think it is the second one. hope it helps! :)
aliina [53]4 years ago
4 0
Your answer would be C. Ginkgo. 
I hope I have helped!

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About how many times more massive is a neon atom than a helium atom?
Anna11 [10]

Answer:

neon is about five times more massive than helium.

Explanation:

got this one right lol

5 0
3 years ago
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scoundrel [369]
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5 0
4 years ago
Read 2 more answers
Determine the mass of oxygen that is needed to react with 33 grams of phosphorus.
Kipish [7]

Answer:

D = Mass =  42.6 g

Explanation:

Given data:

Mass of phosphorus react = 33 g

Mass of oxygen needed = ?  

Solution:

Chemical equation:

4P + 5O₂     →      2P₂O₅

Number of moles of phosphorus:

Number of moles = mass/molar mass

Number of moles = 33 g/ 30.97 g/mol

Number of moles = 1.065 mol  

now we will compare the moles of phosphorus and oxygen.  

               P         :       O₂  

               4         :        5  

        1.065        :        5/4×1.065 = 1.33mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.33 mol × 32 g/mol  

Mass = 42.6 g

Thus, 43.6 g of oxygen needed to react with 33 g of phosphorus.

8 0
3 years ago
The half-life of U234 is 25200 years. How much of a 100 gram sample remains after 352800 years?
lord [1]
The answer is um hold on need a dictionary lol jk but i will be right back to help you
6 0
3 years ago
What is the volume of 0.80 grams of O2 gas at stp?
sergey [27]

<u>Answer: </u>The volume occupied by O_2 at STP is 0.56 L.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of oxygen = 0.80 g

Molar mass of oxygen = 32 g/mol

Putting values in above equation, we get:

\text{Moles of oxygen}=\frac{0.80g}{32g/mol}=0.025mol

<u>At STP:</u>

1 mole of a gas occupies 22.4 L of volume.

So, 0.025 moles of oxygen gas will occupy = 22.4\times 0.025=0.56L of volume.

Hence, the volume occupied by O_2 at STP is 0.56 L.

4 0
4 years ago
Read 2 more answers
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