Answer:
d.
Step-by-step explanation:
if x varies directly as y,
x = ky
8 = 12k
12k = 8
k = 8/ 12
k = 2/3,
x = 2/3 y
now substitute the value of any of the numbers of each pair, and check if it works:
for e.g, find x when y = 15
x = 2/3y
x = 2/3 × 15
x = 10
since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .
ii) x = 2/3y
x = 2/3 × 3, when y = 3
x = 2
hence, this is also a possible pair of x and y values.
iii) x = 2/3y
x = 2/3 × 9 when y = 9
x = 6
again, a possible pair of x and y values.
iv) x = 2/3y
x = 2/3 × 20 when y = 20
x = 40/3
here, when y = 20, x is not 15. it is 40/3.
thus, it can be determined that this is not a possible pair of x and y values.
please try to understand and have a great day!
Answer:
Hello,
Answer 6
Step-by-step explanation:
The smallest number to be susbtracted is 6
Answer:
Step-by-step explanation:
divide each by x
Answer: think the answers near tenth
Answer:
(0,6).
Step-by-step explanation:
Consider the standardised form of y=ax2+bx+c. Written as y=a(x2+bax)+c. xvertex=(−12)×ba → (−12)×0−1=0.
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