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ELEN [110]
2 years ago
7

Evaluate the expression бу — x when x = 6 and y = 4

Mathematics
1 answer:
s2008m [1.1K]2 years ago
8 0
6y-x
you have to plug in the numbers for x and y so it would be (6x4)-6 then you you solve this you do whats in parentheses first. Your problem should look like this 24-6 then you subtract that and you get 18. 18 will be your final answer.
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When rolling a standard number cube: P(3 and then even)?
Fynjy0 [20]
B could be the only answer
8 0
3 years ago
Please help quickly as possible thank you! ​
tensa zangetsu [6.8K]

Multiply Q\cdot P, quantity and price,

1.2\cdot5.95=7.14.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
PLS PLS HELP ME!!!
LenaWriter [7]

Answer:

32, 64)

O (2-4)

0 (-2,-4)

O (-32, 64)

4 0
2 years ago
Differentiate the following functions (x^3+1)(x-2)÷x^2​
Masja [62]

Given:

The given function is:

\dfrac{(x^3+1)(x-2)}{x^2}

To find:

The differentiation of the given function.

Solution:

Consider the given function,

y=\dfrac{(x^3+1)(x-2)}{x^2}

It can be written as:

y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}

y=\dfrac{x^4-2x^3+x-2}{x^2}

y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}

y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}

Differentiate with respect to x.

y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})

y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})

y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}  

Therefore, the differentiation of the given function is 2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}.

8 0
3 years ago
[50 POINTS]
Zina [86]
A^2 + 2AB + B^2 = (A + B)^2 ==>

16X^2 + 40X + 25 = 
= (4X)^2 + 2*4*5X + 5^2 = 
= (4X + 5)^2 

<span>(4x + 5)(4x + 5)</span>
5 0
3 years ago
Read 2 more answers
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