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2 years ago

Evaluate the expression бу — x when x = 6 and y = 4

1 answer:

s2008m [1.1K]2 years ago

8 0

6y-x
you have to plug in the numbers for x and y so it would be (6x4)-6 then you you solve this you do whats in parentheses first. Your problem should look like this 24-6 then you subtract that and you get 18. 18 will be your final answer.

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When rolling a standard number cube: P(3 and then even)?

Fynjy0 [20]

B could be the only answer

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3 years ago

Please help quickly as possible thank you!

tensa zangetsu [6.8K]

Multiply $Q\cdot P$ , quantity and price,

$1.2\cdot5.95=7.14$ .

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3 years ago

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LenaWriter [7]

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2 years ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago

[50 POINTS]

Zina [86]

A^2 + 2AB + B^2 = (A + B)^2 ==>

16X^2 + 40X + 25 =
= (4X)^2 + 2*4*5X + 5^2 =
= (4X + 5)^2

<span>(4x + 5)(4x + 5)</span>

5 0

3 years ago

Read 2 more answers