Answer:
816 cm²
Step-by-step explanation:
Surface area of the composite figure = (surface area of the larger rectangular prism + surface area of the smaller rectangular prism) - area of the side of the smaller rectangular prism that is joined to the bigger prism.
✔️Surface area of the larger rectangular prism:
Area = L*W*H = 20*5*6 = 600 cm²
✔️surface area of the smaller rectangular prism:
Area = L*W*H = 12*4*6 = 288 cm²
✔️area of the side of the smaller rectangular prism that is joined to the bigger prism.
Area = L*W = 12*6 = 72 cm²
Surface area of the composite = (600 + 288) - 72 = 888 - 72 = 816 cm².
Circumference= 2πr
Circumference= perimeter
14.28km= 2(3.14)r
14.28= 6.2831853072r
divide both sides by 6.2831853072
2.27= r
ANSWER: The radius is 2.27km
Hope this helps! :)
Answer:
The leading coefficient is -3
The constant is 2
Step-by-step explanation:
The standard form of a polynomial is the descending order, that means that it must be written according from its higher power, down straight to the coefficient with no variable.
Hence, the leading coefficient is the one that is next to the highest exponent of the polynomial, in this case: =3x2.
The second term is 5x
And the last is 2. the constant
Hey there!
14 + 3y < 65
SOME people replace “<”, “>”, “≥”, or “≤” as an equal sign (=) to make it easier to solve
14 + 3y < 65
14 + 3y = 65
SUBTRACT by 14 on both of your sides
3y + 14 - 14 = 65 - 14
CANCEL out: 14 - 14 because that gives you 0
KEEP: 65 - 14 because it helps you solve for “y”
**65 - 14 = 51**
NEW EQUATION: 3y = 51
DIVIDE by 3 both of your sides
3y/3 = 51/3
CANCEL out: 3/3 because that gives you 1
KEEP: 51/3 because it gives you the value of “y”
NEW EQUATION: y = 51/3
**51/3 = 17**
Answer: y = 17 ☑️
☑️ OVERALL ANSWER FOR YOU: y < 17 ☑️
NOTE: it’s an OPEN circle SHADED to the LEFT
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
Answer:
Case 1:
Case 2:
Case 3: Not possible
Step-by-step explanation:
Given
See attachment for illustration of each case
Required
Find AB and BC
Case 1:
Using Pythagoras theorem in ANB, we have:
This gives:
Take square roots of both sides
To calculate BC, we consider ANC, where:
Collect like terms
Take square roots
So:
Case 2:
Using Pythagoras theorem in ANB, we have:
This gives:
Collect like terms
Take square roots of both sides
To calculate BC, we consider ABC, where:
Collect like terms
Take square roots
Case 3:
This is not possible because in ANC
The hypotenuse AN (24) is less than AC (40)
