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3 years ago

8

(10-1)(10-2)(10-3)(10-10)

1 answer:

Goryan [66]3 years ago

6 0

Answer:

0

Step-by-step explanation:

(10-1=9)(10-2=8)(10-3=7)(10-10=0)

9*8*7*0=0

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Will give brainliest please explain how

aivan3 [116]

Answer:

x = 5/4

Step-by-step explanation:

√2+√2+√2+√2 = 2^x

4√2 = 2^x

4√2 = $2^{\frac{5}{2} }$ = $2^{x}$

x = 5/2

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3 years ago

Brainiest to whoever correct

LuckyWell [14K]

Answer: 2nd one.

Step-by-step explanation:

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2 years ago

At a rate of 4% you paid $144 in interest over to year. What was the original amount of your loan

dem82 [27]

$\bf ~~~~~~ \textit{Simple Interest Earned}
\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$144\\
P=\textit{original amount deposited}\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &1
\end{cases}
\\\\\\
144=P(0.04)(1)\implies \cfrac{144}{(0.04)(1)}=P\implies 3600=P$

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4 years ago

How do i find the answer to this expression? x ²+16x-32=-7

kolbaska11 [484]

Answer:

I dunno

Step-by-step explanation:

maybe it is Solve the equation for xx by finding aa, bb, and cc of the quadratic then applying the quadratic formula.

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2 years ago

A train travels a distance of 60 km at uniform speed. If the speed of the train was reduced by 10 kmh-1, the time taken to trave

tester [92]

Answer:

<u>Initial</u><u> </u><u>speed</u><u> </u><u>is</u><u> </u><u>3</u><u>2</u><u> </u><u>m</u><u>/</u><u>s</u>

At uniform speed, acceleration is 0, (a = 0).

When speed reduced, (v - u) = 2.78 ms-¹, t = 1800 sec, s = 60 ,000 metres.

From first equation of motion:

${ \boxed{ \bf{v = u + at}}} \\ { \tt{(v - u) = at}}$

substitute:

${ \tt{2.78 = (a \times 1800)}} \\ { \tt{acceleration = 0.0015 \: {ms}^{ - 2} }}$

from second equation of motion:

${ \boxed{ \bf{s = ut + \frac{1}{2} a {t}^{2} }}}$

substitute:

${ \tt{60000 = 1800u + ( \frac{1}{2} \times 0.0015 \times {1800}^{2}) }} \\ { \tt{1800u = 57570}} \\ { \tt{u = 32 \: m {s}^{ - 1} }}$

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3 years ago