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lord [1]
4 years ago
6

A person with his ear to the ground, sees a huge stone strikethe concrete pavement. A moment later two sounds are heard from the

impact: one travels n the air and the other in the concrete, andthey are 2.2 s apart. How far away did the impact occur?
*The speed of sound for air is 343 m/s, for concrete˜3000.
Physics
1 answer:
KIM [24]4 years ago
3 0

Answer:

d= 852.01 m

Explanation:

Given that

Speed of sound in air u= 343 m/s

Speed of sound in concrete v= 3000  m/s

Lets take time taken by sound in the concrete is t then the time taken by sound in air will be t+2.2 s  .

The distance (d)travel will be same in both the cases.

We know that

Distance =  Velocity x time

So

d= 3000 x t  = 343 x (t+2.2)

3000 t = 343 t + 343 x 2.2

t= 0.284 s

So the distance d

d= 3000 x 0.284 m

d= 852.01 m

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The answer using the graphical method and analytical method of vector addition will always be

C. Same

Analytic method means adding vectors (x₁,y₁) and (x₂,y₂) give (x₁+x₂,y₁+y₂)

Example: Addition of (2,3) and (1,1) gives (3,4)

Solving it graphically will also give (3,4)

4 0
4 years ago
A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position
irga5000 [103]

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(c) The angular frequency of the oscillation is 7.885 rad/s.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

  • <em>Mass of the ball, m = 2.4 kg</em>

<em />

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz

The angular frequency of the oscillation is calculated as follows;

\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s

The force constant of the spring is calculated as follows;

\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m

Learn more about general wave equation here: brainly.com/question/25699025

4 0
3 years ago
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snow_tiger [21]
<span>If the forces are acting in exactly opposite directions, they will subtract, and the magnitude of the resultant force is 6 N. This is the minimum resultant force, so that rules out (1). Similarly, if they act in exactly the same direction, they will add, and the resultant force is 18 N. This will be the maximum resultant force. That rules out (3) and (4). Thus, at some angle (between 0 and 180 degrees), you COULD find a resultant force of 15 N.</span>
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3 years ago
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A closed container is filled with oxygen. the pressure in the container is 425 kpa . what is the pressure in millimeters of merc
julia-pushkina [17]

Given that,

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Since, we know that,

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The pressure of container filled with oxygen is 3187.76 millimeter of mercury.

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3 years ago
A ship’s wheel is rotated 128 degrees. Its radius is 22 cm. How far would a point on the wheel’s edge move in this rotation?
ZanzabumX [31]
To solve this problem, we use this formula:
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where
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Plugging in the given values and converting degrees to radians
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7 0
3 years ago
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