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Burka [1]
3 years ago
5

A closed container is filled with oxygen. the pressure in the container is 425 kpa . what is the pressure in millimeters of merc

ury? express the pressure numerically in millimeters of mercury.
Physics
1 answer:
julia-pushkina [17]3 years ago
4 0

Given that,

Pressure = 425 Kpa

Pressure in millimeter of mercury = ?

Since, we know that,

1 Kpa = 7.5 millimeter of mercury

425 Kpa = 425 *7.5 millimeter of mercury

425 Kpa = 3187.76 millimeter of mercury.

The pressure of container filled with oxygen is 3187.76 millimeter of mercury.

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Explanation:

The kicker exerts more force of the football which is why the football moves when its kicked.

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What is the mathematical relationship between wavelength and velocity?
gavmur [86]

Answer:A wave has a wavelength λ, which is the distance between adjacent identical parts of the wave. The wave velocity and the wavelength are related to the wave's frequency and period by vw=λT or vw=fλ.

Explanation:

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What do magnets never do?<br><br><br> This is science btw.
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2 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
A bottle of water with mass 0.9 kg is left out in the sun, the radiation from the sun warms up the water bottle. If the water bo
natita [175]

Answer:

Final temperature, T2 = 314.9 Kelvin

Explanation:

Given the following data:

Mass = 0.9kg

Initial temperature, T1 = 10°C to Kelvin = 10 + 273 = 283K

Quantity of heat = 120,000 J

Specific heat capacity = 4182 j/kgK

To find the final temperature;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making dt the subject of formula, we have;

dt = \frac {Q}{mc}

Substituting into the equation, we have;

dt = \frac {120000}{0.9*4182}

dt = \frac {120000}{3763.8}

dt = 31.9K

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 31.9 + 283

T2 = 314.9 Kelvin

8 0
3 years ago
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