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4 years ago

The answer using the graphical method and analytical method of vector addition will always be.

Physics

1 answer:

Alex17521 [72]4 years ago

4 0

The answer using the graphical method and analytical method of vector addition will always be

C. Same

Analytic method means adding vectors (x₁,y₁) and (x₂,y₂) give (x₁+x₂,y₁+y₂)

Example: Addition of (2,3) and (1,1) gives (3,4)

Solving it graphically will also give (3,4)

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Come si compongono due forze che agiscono in diversi punti di un corpo rigido? Oof

bagirrra123 [75]

Answer:

Explanation:

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3 years ago

The heating of the filament is what causes the light production (photon emission), and heating is caused by the current in the l

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Answer:

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4 years ago

Two parallel-plate capacitors have the same dimensions, but the space between the plates is filled with air in capacitor 1 and w

Aleks [24]

Explanation:

The capacitance in two parallel-plate capacitors is:

$C=\frac{K\epsilon_oA}{d}$

For air, we have $K_1=1$

For plastic, we have $K_2=2.25$

Hence:

$C_1=\frac{K_1\epsilon_oA}{d_1}=\frac{\epsilon_oA}{d_1}\\C_2=\frac{K_2\epsilon_oA}{d_2}=2.25(\frac{\epsilon_oA}{d_2})$

a) Recall that the potential difference between the plates is the same ( $V_1=V_2=V$ ). The electric field is given by:

$E_1=\frac{V_1}{d_1}=\frac{V}{d_1}\\E_2=\frac{V_2}{d_2}=\frac{V}{d_1}$

The potential difference is defined as:

$V_1=\frac{Q_1}{C_1}=V\\V_2=\frac{Q_2}{C_2}=V$

Replacing:

$E_1=\frac{Q_1}{C_1d_1}\\E_2=\frac{Q_1}{C_1d_2}\\\\E_1d_1=\frac{Q_1}{C_1}\\E_2d_2=\frac{Q_1}{C_1}\\E_1d_1=E_2d_2\\\frac{E_1}{E_2}=\frac{d_2}{d_1}$

b) The energy is defined as:

$U=\frac{1}{2}CV^2$

So:

$U_1=\frac{1}{2}C_1V_1^2=\frac{1}{2}C_1V^2\\U_2=\frac{1}{2}C_2V_2^2=\frac{1}{2}C_2V^2\\U_1=\frac{1}{2}\frac{\epsilon_oA}{d_1}V^2\\U_2=\frac{1}{2}\frac{2.25\epsilon_oA}{d_2}V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=V^2\\\frac{2U_1d_1}{\epsilon_oA}=V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=\frac{2U_1d_1}{\epsilon_oA}\\\frac{U_1}{U_2}=0.44\frac{d_2}{d_1}$