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zvonat [6]
3 years ago
5

Can someone please help

Mathematics
1 answer:
blagie [28]3 years ago
8 0

Answer:

Which one

Step-by-step explanation:

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zepelin [54]

Answer: 94.3 meters

Step-by-step explanation:

4 0
3 years ago
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Find the range of the data.
Cloud [144]

Answer:

8

Step-by-step explanation:

Range is found by taking the largest number and subtracting the smallest number

The largest number is 9

The smallest number is 1

9-1 =8

The range is 8

3 0
3 years ago
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2.
mihalych1998 [28]
To solve this we are going to use the future value of annuity due formula: FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]
where
FV is the future value P is the periodic payment r is the interest rate in decimal form n is the number of times the interest is compounded per year k is the number of payments per year t is the number of years

We know for our problem that P=295 and t=6. To convert the interest rate to decimal for, we are going to divide the rate by 100%:
r= \frac{10}{100}
r=0.1
Since the payment is made quarterly, it is made 4 times per year; therefore, k=4.
Since the type of the annuity is due, payments are made at the beginning of each period, and we know that we have 4 periods, so n=4.
Lets replace those values in our formula:

FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]
FV=(1+ \frac{0.1}{4} )*295[ \frac{(1+ \frac{0.1}{4} )^{(4)(6)} -1}{ \frac{0.1}{4} }  ]
FV=9781.54

We can conclude that the amount of the annuity after 10 years is $9,781.54
6 0
3 years ago
Q(–1, a) is 4 √5 units away from P(3, –2). Find all possible values of a.
vagabundo [1.1K]

Answer:

a=6,-10

Step-by-step explanation:

4\sqrt{5}=\sqrt{(3+1)^2+(-2-a)^2} \\squaring\\80=16+(2+a)^2\\80-16=(2+a)^2\\(a+2)^2=64\\taking~square ~root\\\\a+2=\pm 8\\either \\a+2=8,\\a=8-2=6\\or\\a+2=-8\\a=-8-2=-10

8 0
3 years ago
Fins the quontient 5)47 and it has to have a remander plzzzzzzzz help meeeee!!!!!!;
timama [110]
See how many 5s there are in 47? There are 9 and also a leftover 2 which is your remainder.<span />
8 0
3 years ago
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