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julsineya [31]
3 years ago
11

Uber charges $0.80 per mile and a booking fee of $2.30. Lyft charges $1.07 per mile with no booking fee. Which of the systems of

equations bests models this situation where c represents the cost and m the number of miles ridden?
Mathematics
1 answer:
gregori [183]3 years ago
8 0

Answer:

Step-by-step explanation:

Let c represent the total cost of booking either Uber or Lyft for x miles.

Let m represent the number of miles ridden with either Uber or Lyft.

Uber charges $0.80 per mile and a booking fee of $2.30. This means that the total cost of riding with Uber for m miles would be

c = 2.30 + 0.8m - - - - - - - - - -1

Lyft charges $1.07 per mile with no booking fee. This means that the total cost of riding with Lyft for m miles would be

c = 1.07m - - - - - - - - - -2

Equation 1 and equation 2 are the system of equations that bests models this situation

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A student earns $7.50 per hour at her part-time job. She wants to earn at least $200.
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Answer:7.50x is greater than or equal to 200

Step-by-step explanation:

She wants to make AT LEAST $200

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3 years ago
The quantity, Q, of a drug in the blood stream begins with 250 mg and decays to one-fifth its value over every 90 minute period.
Mazyrski [523]

Answer:

a=250 \, mg\\\\b=5\\\\T= 90'

Step-by-step explanation:

We have that Q(t) = a\cdot b^{-\frac{t}{T}} \\

Where t is the time (in minutes) and for the sake of dimensional consistency, let's assume that T is also in minutes, b is an adimensional number, and a is in mg.  So we will have Q in mg as a consequence.

We now want to find out what values these constants might take. Let's see what happens when t=0, that is, just as we start. At that point, we have that the amount of drug in the bloodstream must be equal to 250mg, thus:

Q(0)= a\cdot b ^{-\frac{0}{T} }=250\,mg\\Q(0)= a=250\,mg

We have found the constant a! It is the initial amount of drug! we have made use of the fact that any number raised to the 0th power is equal to one.

Now, we know that every 90 minutes, the amount of drug decreases to one fifth of its former value. How do we put this in mathematical form? Like so:

Q(t+90')=Q(t)/5

That is, 90 minutes after time t the amount of drug will be one fifth of the amount of drug at time t. Let's expand the last equation:

Q(t+90')=Q(t)/5\\\\a\cdot b^{-\frac{t+90'}{T} }=a\cdot b^{-\frac{t}{T} }/5\\\\ b^{-\frac{t+90'}{T} }=b^{-\frac{t}{T} }/5\\\\b^{-\frac{t}{T} }b^{-\frac{90'}{T} }=b^{-\frac{t}{T} }/5\\\\b^{-\frac{90'}{T} }=\frac{1}{5}

Now the last expression isn't enough to determine both T and b, but that also means that we have some freedom in how we choose them. What seems most simple is to pick T=90' and thus we will get:

b^{-1 }=\frac{1}{5}\\\\\frac{1}{b}= \frac{1}{5}\\\\b=5

And that is our final result.

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