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Bogdan [553]
3 years ago
13

A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviat

ion of 50. If an applicant is randomly selected, find the probability of a rating that is between 170 and 220. Group of answer choices 0.2257 0.1554 0.0703 0.3811
Mathematics
1 answer:
Alika [10]3 years ago
6 0

Answer:

P(170

And we can find the probability with this difference:

P(-0.6

And using the normal standard table or excel we got:

P(-0.6

And the best answer would be:

0.3811

Step-by-step explanation:

Let X the random variable that represent the ratings of a population, and for this case we know the distribution for X is given by:

X \sim N(200,50)  

Where \mu=200 and \sigma=50

We are interested on this probability

P(170

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

Using the z score we got:

P(170

And we can find the probability with this difference:

P(-0.6

And using the normal standard table or excel we got:

P(-0.6

And the best answer would be:

0.3811

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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
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Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

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2 years ago
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