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Bogdan [553]
3 years ago
13

A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviat

ion of 50. If an applicant is randomly selected, find the probability of a rating that is between 170 and 220. Group of answer choices 0.2257 0.1554 0.0703 0.3811
Mathematics
1 answer:
Alika [10]3 years ago
6 0

Answer:

P(170

And we can find the probability with this difference:

P(-0.6

And using the normal standard table or excel we got:

P(-0.6

And the best answer would be:

0.3811

Step-by-step explanation:

Let X the random variable that represent the ratings of a population, and for this case we know the distribution for X is given by:

X \sim N(200,50)  

Where \mu=200 and \sigma=50

We are interested on this probability

P(170

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

Using the z score we got:

P(170

And we can find the probability with this difference:

P(-0.6

And using the normal standard table or excel we got:

P(-0.6

And the best answer would be:

0.3811

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PLSS HELP ASAPPPPP ! <br><br><br> :}}}}}}}}}}}}
MAXImum [283]

Answer:

0.5

Step-by-step explanation:

First find the mean of the data

3+4+4+5 = 16

16/4 = 4

Find the distance of each data to the mean

4-3 =  1

5-4= 1

4-4 = 0

4-4 = 0

Now find the mean of those

1+1+0+0 = 2

2/4

MAD = 0.5

8 0
3 years ago
Endent Practice
Vikki [24]

Answer:

Part A: The unit that would be best to describes the situations is to the mile

Part B: 4 significant figures

Part C: 1,450 miles

Part D: He is not correct

Step-by-step explanation:

Part A: By unit conversion, we have;

1 mile = 1,760 yards

Given that the distance from Ottawa, Canada to Jackson Mississippi is 2,552,000 yards it would best simplified into miles

Part B: The number of significant digits in the reporters estimate are the non-zero digits before the zeros in the number figure which are 2, 5, 5, and 2 or 4 significant figures

Part C: 2,552,000 yards = 2,552,000 yards/(1,760 yards/mile) = 1,450 miles

Part D: Given that the distance from Jackson to Tucson = 7,159,680 feet, we have;

1 mile = 5,280 feet

Therefore;

7,159,680 feet = 7,159,680 feet/(5,280 feet/mile) = 1,356 miles

Therefore, the claim that the distance from Jackson to Tucson which is 1,356 miles is further than the distance from Ottawa, Canada to Jackson Mississippi which is 1,450 miles is not correct because;

The distance from Jackson to Tucson 1,356 miles \ngtr 1,450 miles which is the distance from Jackson to Ottawa

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I would most likely go with C.
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186 chairs
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The ratio would be 14:6
If you reduce it it would be 7:3
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