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3 years ago

What is the period of the sinusoid given by y= -3 cos (2pi/5x)?

Mathematics

1 answer:

8090 [49]3 years ago

7 0

<h3>Answer: 5</h3>

Work Shown:

y = -3cos(2pi/5x) is in the form y = A*cos(Bx) where |A| is the amplitude and B helps determine the period T. In this case, B = 2pi/5

T = 2pi/B

T = 2pi/(2pi/5) ... replace B with 2pi/5

T = (2pi/1) divided by (2pi/5)

T = (2pi/1) * (5/2pi)

T = 5 ... note how the '2pi' terms canceled out

So the period is 5

This means that every 5 units on the x axis is when the graph repeats itself.

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3 years ago

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svetoff [14.1K]

Given:

Point (7,12) is rotated 1260° counterclockwise about the origin.

To find:

The x-coordinate of the point after this rotation.

Solution:

If a point is rotated 360 degrees then its coordinates remains unchanged.

If a point is rotated 180 counterclockwise about the origin degrees, then

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We know that,

$1260^\circ=1080^\circ+180^\circ$

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After $3\times 360^\circ$ rotation the coordinates of points remains same, i.e., (7,12). So, after that (7,12) is rotated 180° counterclockwise about the origin.

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3 years ago

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Step-by-step explanation:

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