All categories

3 years ago

Which statement is false?

2 answers:

8 0

Trigonometric functions which are related by having the same value at complementary angles are called cofunctions. Cofunctions of complementary angles are equal.

A. csc 20' = csc(90-70)=sec 70

B. cos 87' = cos (90-3)=sin 3'

C. csc 40' = csc(90-50) =sec50'

D. tan 15' = tan(90-75)= cot 75'

Among all the option c is not correct.

Option C is false.

arlik [135]3 years ago

5 0

Answer: Option <span>C. csc 40' = sin 50'
Because csc and sin are not cofunctions</span>

You might be interested in

Please answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!

olya-2409 [2.1K]

Answer:

-10

Step-by-step explanation:

-(x-5) ^2+25

-x+5^2+25

-5 -5

-x^2+20

-2x+20

---- ----

-2 -2

x=-10

// have a great day //

3 0

2 years ago

Write an exponential function in the form y = ab that goes through points (0,19)<br>and (5,4617).

gtnhenbr [62]

Answer:

y = 1/2 (2)x

Step-by-step explanation:

Using the equation y = abx , substitute both of your given points into that equation.

2 = ab2 and 4 = ab3 Solve each equation for a.

2⁄b2 and 4⁄b3 = a Therefore, 2⁄b2 = 4⁄b3

Cross multiply: 2b3 = 4b2 Divide both sides by b2

2b = 4 a = 2/4 = 1/2

b = 2

3 0

2 years ago

Jacob wants to get a video gamecrental account. The rental store charges 10 per month charges no matter how many video games wer

san4es73 [151]

Answer:

add

Step-by-step explanation:

4 0

2 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

4 0

2 years ago

Read 2 more answers

True or false: equilateral triangles can be classified as acute right or obtuse

yarga [219]

Answer:

it is only acute

Step-by-step explanation:

False: equilateral triangle has 3 equal sides and 3 equal angles measure 60 degrees

7 0

2 years ago

Read 2 more answers