Mark and Mike are brothers. The sum of their ages is eleven. Mike's age is ten

Mathematics

2 answers:

ivann1987 [24]3 years ago

8 0

Answer:mark is 7. Mike is 4

Step-by-step explanation:x+y=11. Y=2x-10 thus substituting for y in equation1 we have x+2x-10=11. 3x-10=11. 3x=11+10. 3x=21. X=21/3. X=7. Mike =(2×7)-10=14-10=4

o-na [289]3 years ago

3 0

Step-by-step explanation:

Mark's age is x

so Mike's age is

$2x - 10$

and we know that the sum of their ages is eleven so:

2x+x- 10 = 11

3x-10=11/+10

3x=21/÷3

x=7

Mark is 7 years old and

Mike is 4 years old.

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The residents of a certain dormitory have collected the following data: People who live in the dorm can be classified as either

Ad libitum [116K]

Answer:

The steady state proportion for the U (uninvolved) fraction is 0.4.

Step-by-step explanation:

This can be modeled as a Markov chain, with two states:

U: uninvolved

M: matched

The transitions probability matrix is:

$\begin{pmatrix} &U&M\\U&0.85&0.15\\M&0.10&0.90\end{pmatrix}$

The steady state is that satisfies this product of matrixs:

$[\pi] \cdot [P]=[\pi]$

being π the matrix of steady-state proportions and P the transition matrix.

If we multiply, we have:

$(\pi_U,\pi_M)*\begin{pmatrix}0.85&0.15\\0.10&0.90\end{pmatrix}=(\pi_U,\pi_M)$

Now we have to solve this equations

$0.85\pi_U+0.10\pi_M=\pi_U\\\\0.15\pi_U+0.90\pi_M=\pi_M$

We choose one of the equations and solve:

$0.85\pi_U+0.10\pi_M=\pi_U\\\\\pi_M=((1-0.85)/0.10)\pi_U=1.5\pi_U\\\\\\\pi_M+\pi_U=1\\\\1.5\pi_U+\pi_U=1\\\\\pi_U=1/2.5=0.4 \\\\ \pi_M=1.5\pi_U=1.5*0.4=0.6$