X, X+2, X+4 ARE THE 3 POSITIVE CONSECUTIVE INTEGERS.
X(X+2)=8+38(X+4)
X^2+2X=8+38X+152
X^2+2X-38X-8-152=0
X^2-36X-160=0
(X-40)(X+4)=0
X-40=0
X=40 ANSWER FOR THE FIRST INTEGER.
40+2=42 FOR THE SECOND INTEGER.
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Answer:
Technically, one (they equal the same thing) but 2 in this case.
Step-by-step explanation:
6 + 6 + 4
6 + 4 + 6
Answer:
x^2 + 2xy + y ^2
Step-by-step explanation:
A = a^2
a = x + y
(x + y) + (x + y)
x^2 + xy + xy + y^2
x^2 + 2xy + y ^2
The last expression: (16-8)x2+4=8x6=48