Answer:
2 to the power of 2 +
Step-by-step explanation:
Distribute
Eliminate redundant parentheses
Subtract the numbers
Combine like terms
Combine like terms... again
Multiply by 1 = 2 to the power of 2 +
For this case we have the following equations:

The break even point occur when C = R:
We have then:

Clearing x we have:

Then, substituting in any of the equations we have:

The break even point is:
(4, 176)
Answer:
The break even point is:
(4, 176)
Step-by-step explanation:
Correct option is
C
0≤r<b
If r must satisfy0≤r<b
Proof,
..,a−3b,a−2b,a−b,a,a+b,a+2b,a+3b,..
clearly it is an arithmetic progression with common difference b and it extends infinitely in both directions.
Let r be the smallest non-negative term of this arithmetic progression.Then,there exists a non-negative integer q such that,
a−bq=r
=>a=bq+r
As,r is the smallest non-negative integer satisfying the result.Therefore, 0≤r≤b
Thus, we have
a=bq1+r1, 0≤r1≤b
I think it’s b
I hope I’m right