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3 years ago

14

A firefighter truck can hold 3000 gallons of water. A firefighter can deliver 160 gallons of water every 2 minutes. How long wil

l it take for the firefighter to empty the tank?

1 answer:

Nady [450]3 years ago

4 0

Answer:

37.5

Step-by-step explanation:

3000/160 = 18.75

18.75 x 2= 37.5

correct me if im wrong please

have a good day luv <3

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Find the pattern and use it to list the next two terms in the sequence.<br> 0, 2, 0, -2, 0, 2,

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In 2002, Tim was twice as old as Sue. In 1997 the sum of their ages was 32. In what year will Sue's age be three-fourths Tim's a

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Answer:

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = <em>X</em> years

In 1997, Let Sue's age = <em>Y</em> years

After 5 years in 2002, Tim's age = (<em>X+ 5) </em>years

After 5 years in 2002, Sue's age = <em>(Y + 5)</em> years

Now, According to question,

<em>X </em>+ <em>Y</em> = 32 (sum of their ages) .......(1)

<em>Y </em>= 32 -<em> X</em>

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of <em>Y</em> in (2)

<em>X </em>+ 5 = 2 (32 - <em>X </em>+ 5)

<em>X </em>+ 5 = 2 (37 - <em>X </em>)

<em>X </em>+ 5 = 74 - 2<em>X </em>

3<em>X </em>=<em> </em>69

<em>X </em>= 69/3 = 23

Now ∵<em> Y</em> = 32 - <em>X </em>and<em> X = </em>23

∴ <em>Y</em> = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after<em> t </em>years = (9 +<em> t) </em>years.

Tim's age after<em> t</em> years = (23 + <em>t</em>) years

According to question,

$(9 + t) = \frac{3}{4} \times(23 + t)$

$4 (9 + t) = 3 (23 + t)$

$36 + 4t = 69 + 3t$

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<em> $t = 33$ </em>

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4 years ago

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3 years ago

A club with five men and six women wish to form a committee. The number of men must be between 1 and 3 (inclusive), and the numb

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We are told that the club has 5 men and 6 women.

Now we want to choose number of men between 1 and 3 with both inclusive and number of women between 2 and 4 with both inclusive.

We'll use the combination formula;

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