Answer:
Step-by-step explanation:
-7z/2 - 2 + z -3
=-5 - 5z/2
Answer:
The function is negative for all real values of x where -6< x < -2
Step-by-step explanation:
Given f(x) = (x + 2)(x + 6)
The graph of the function is as shown in the attached figure.
As shown, we can deduce the following:
The function is positive for all real values of x where x > -2 and x < -6
The function is zero at x = -2 and x = -6
The function is negative for all real values of x where -6 < x <-2
Compare the observations to the given statements:
So, The true statement is The function is negative for all real values of x where -6 < x <-2
Answer:
Rock travels about 8.2x²meters higher on the moon than on the Earth.
Step-by-step explanation:
Expression showing the height of a rock thrown into the air at Earth is,
f(x) = -9.8x² + 10x + 1.5
Similarly, expression showing the height of rock thrown on the moon is,
g(x) = -1.6x² + 10x + 1.5
Difference in the height of the rock thrown on moon = g(x) - f(x)
= (-1.6x² + 10x + 1.5) - ( -9.8x² + 10x + 1.5)
= -1.6x² + 9.8x² + 10x - 10x + 1.5 - 1.5
= 8.2x²
Therefore, rock travels about 8.2x²meters higher on the moon than on the Earth.
Answer:
The temperature a t = 0 is 190 °F
The temperature a t = 1 is 100 °F
The temperature a t = 2 is 77.5 °F
It takes 1.5 hours to take the coffee to cool down to 85°F
It takes 2.293 hours to take the coffee to cool down to 75°F
Step-by-step explanation:
We know that the temperature in °F, of a cup of coffee t hours after it is set out to cool is given by the following equation:

a) To find the temperature a t = 0 you need to replace the time in the equation:

b) To find the temperature after 1 hour you need to:

c) To find the temperature after 2 hours you need to:

d) To find the time to take the coffee to cool down
, you need to:






e) To find the time to take the coffee to cool down
, you need to:


Step-by-step explanation:
A system of linear equations usually has a single solution, but sometimes it can have no solution (parallel lines) or infinite solutions (same line).