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BartSMP [9]
3 years ago
8

List all number sets that apply to each number.

Mathematics
1 answer:
Airida [17]3 years ago
8 0
Yeah i agree with them y=10
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A.47

Step-by-step explanation:

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9) first option 10)last option
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G(x) = 4x + 2
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4x \times 2x + 4x \times 5 + 2 \times 2x + 2 \times 5 = 8x {}^{2} + 24x + 10

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What is the product ?
Olenka [21]

Answer:

The answer to your question is:

Step-by-step explanation:

   \frac{x^{2}-16 }{2x + 4} \frac{x^{3}-2x^{2} + x }{x^{2}+ 3x - 4}

Factorize    \frac{(x+4)(x-4)}{2(x+2)}  \frac{x(x^{2}-2x + 1) }{(x+4)(x-1)}

Factorize    \frac{(x+4)(x-4)}{2(x+2)} \frac{x(x-1)^{2} }{(x+4)(x-1)}

Simplify      \frac{x(x-4)}{2(x+2)}

7 0
4 years ago
What are the coordinates of the inflection point on the graph of y=(x+1)arctanx
Dennis_Churaev [7]

Inflection point is the point where the second derivative of a graph is zero.

y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2

Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2

Therefore, E(1, pi/2).


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0
3 years ago
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