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3 years ago

What fraction must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions

Mathematics

1 answer:

DanielleElmas [232]3 years ago

8 0

Answer:

so 1/3 must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions.

Step-by-step explanation:

let the fraction be x

(1/4 + 1/6)-x = 1/12

or, 10/24 - x = 1/12

or, 5/12-1/12 = x

so, x = 4/12 = 1/3

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Trava [24]

Option A

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Solution:

Given that we have to write $y = \frac{1}{6}x+7$ in standard form

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Given equation is:

$y = \frac{1}{6}x+7$

Let us convert the above equation into standard form

$y = \frac{x}{6} + 7$

$y = \frac{x}{6} + \frac{7}{1}$

Make the denominator same in R.H.S

$y = \frac{x}{6} + \frac{7 \times 6}{1 \times 7}$

Solve the above equation

$y = \frac{x}{6} + \frac{42}{6}$

$y = \frac{x+42}{6}$

Move 6 from R.H.S to L.H.S

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Bring all the terms to one side, leaving only constant on R.H.S

$-x + 6y = 42$

The above equation is of form Ax + By = C

Thus option A is correct

3 0

3 years ago

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-BARSIC- [3]

Answer:

Brainliest?

Step-by-step explanation:

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Answer:

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