Answer:
Occupation -> a job or profession: his prime occupation was as editor.
• a way of spending time: a game of cards is a pretty harmless occupation.
2 the action, state, or period of occupying or being occupied by military force: the Roman occupation of Britain | the Nazi occupation.
• the action of entering and taking control of a building: the workers remained in occupation until October 16.
3 the action or fact of living in or using a building or other place: a property suitable for occupation by older people.
Step-by-step explanation:
hope it helps
Step-by-step explanation:
The top part is a cone. It's volume is:
V = ⅓ π r² h
where r is the radius (half the diameter) and h is the height.
The bottom part is a cylinder. It's volume is:
V = π r² h
where r is the radius (half the diameter) and h is the height.
The radius of the cone is 36/2 = 18 ft, and the height is 12 ft. So the volume is:
V = ⅓ π (18 ft)² (12 ft)
V = 4,071.5 ft³
The radius of the cylinder is 36/2 = 18 ft, and the height is 39 ft. So the volume is:
V = π (18 ft)² (39 ft)
V = 39,697.2 ft³
Therefore, the total volume is:
4,071.5 ft³ + 39,697.2 ft³ ≈ 43,769 ft³
Intercept form is: y = a(x - p)(x - q)
It is given that: p = 14, q = -6, x = 14, y = 4
4 = a(14 - 12)(14 - (-6))
4 = a(2)(20)
4 = 40a
Answer: y = 
(x - 14)(x + 6)
The two parabolas intersect for
and so the base of each solid is the set
The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, 
. But since -2 ≤ x ≤ 2, this reduces to 
.
a. Square cross sections will contribute a volume of
where ∆x is the thickness of the section. Then the volume would be
where we take advantage of symmetry in the first line.
b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of
We end up with the same integral as before except for the leading constant:
Using the result of part (a), the volume is
c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is
and using the result of part (a) again, the volume is
