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Rina8888 [55]
3 years ago
14

An equilateral triangle has an altitude length of 33 feet. Determine the length of a side of the triangle.

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

38.11 feet

Step-by-step explanation:

all three corners of an equilateral triangle are 60°

sin 60° = 33/x

0.8660 =33/x

x = 38.11 feet

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HURRY will mark brainliest <br>which one of the following graphs is not a function?? :)​
bonufazy [111]

Answer:

I think its A i'm sorry if its wrong

Step-by-step explanation:

5 0
3 years ago
Maria is draining her hot tub at a rate of 5.5 gallons per minute. Is the amount of water left in the pool a function of the amo
AleksandrR [38]

The amount of water in the pool after t minutes is modeled by the linear function V(t) = V(0) - 5t, hence it is a function of time.

A <em>linear function</em> for the amount of water in the pool, considering that it is <u>drained at a rate of a gallons per minute</u>, is modeled by:

V(t) = V(0) - at

  • In which V(0) is the initial volume.

In this problem, draining her hot tub at a rate of <u>5.5 gallons per minute</u>, hence a = 5.5, and:

V(t) = V(0) = 5.5t

Which is a function of time.

To learn more about linear functions, you can take a look at brainly.com/question/13488309

8 0
2 years ago
Evaluate x ÷ y for x = 3 and y = 12.
eduard

Answer:

1/4 or 0.25

Step-by-step explanation:

Lets plug x and y into the equation. We now have 3/12, which would be equal to 1/4 or 0.25

6 0
3 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
36 is what percent of 200
Andrews [41]

Answer:

18

Step-by-step explanation:

I used a percentage calculator to get you the best answer possible. :) Have a nice day!

3 0
3 years ago
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