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3 years ago

Dennis arrived at Sullivan's at 10:15am the store opens at 11:00 how long will he have to wait

Mathematics

2 answers:

steposvetlana [31]3 years ago

6 0

He will have to wait 45 minutes

kupik [55]3 years ago

6 0

He would have to wait 45 minutes.
Hope I this helps.

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Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$

8 0

3 years ago

The students at Kayla's school are forming teams of three students for a quiz bowl competition. Kayla is assuming that each memb

scZoUnD [109]

There are 2 instances of hhh (all girls) in the 50 trials, so the experimental probability is 2/50 = 4/100 = 0.04.

5 0

3 years ago

What is the rate of change for the sequence shown below. (1,2) (2,2.5) (3,3) (4,3.5) (5,4)

Nataly [62]

Answer:

0.5

Step-by-step explanation:

The given ordered pairs are: (1,2) (2,2.5) (3,3) (4,3.5) (5,4)

The corresponding sequence is :

2,2.5,3,3.5, 4,....

We can see that there is a common difference of d=0.5.

Better still we could use the slope formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

We substitute the point (1,2) and (2,2.5).

The rate of change of this sequence is:

$m = \frac{2.5 - 2}{2 - 1} = \frac{0.5}{1} = 0.5$

5 0

3 years ago

Simplify (x^3/x^2)^2 . Explain your steps.

Helen [10]

Answer:

Step-by-step explanation:

(x^3

x^2)^2

X³ )²

X²

X³*²

X²*²

X ⁶

X⁴

X ⁶-⁴ = X²

8 0

3 years ago

How would you solve these 2 maths problems?

sweet-ann [11.9K]

Answer:

see explanation

Step-by-step explanation:

(9)

Expand and simplify right side and compare coefficients of like terms on left side.

(x - 2)(x² + ax + b) + c

= x³ + ax² + bx - 2x² - 2ax - 2b + c

= x³ + x²(a - 2) + x(b - 2a) - 2b + c

compare with

x³ + 2x² - 3x + 4

x² terms

a - 2 = 2 ( add 2 to both sides )

a = 4

x terms

b - 2a = - 3 ← substitute a = 4

b - 8 = - 3 ( add 8 to both sides )

b = 5

constant terms

- 2b + c = 4 ← substitute b = 5

- 10 + c = 4 ( add 10 to both sides )

c = 14

Thus a = 4, b = 5 and c = 14

-------------------------------------------------

(10)

Since both functions cross the x- axis at - 2 then (- 2, 0) satisfies both, that is

f(- 2) = $(-2)^{4}$ + a(- 2)³ + b(- 2)² + 36(- 2) + 144 = 0, that is

- 16 - 8a + 4b - 72 + 144 = 0

- 8a + 4b + 56 = 0

- 8a + 4b = - 56 → (1)

and

g(- 2) = $(-2)^{4}$ + (a + 3)(- 2)³ - 23(- 2)² + (b + 10)(- 2) + 40 = 0, that is

- 16 - 8(a + 3) - 92 - 2(b + 10) + 40 = 0

- 16 - 8a - 24 - 92 - 2b - 20 + 40 = 0

- 8a - 2b - 112 = 0

- 8a - 2b = 112 → (2)

Subtract (1) from (2) term by term

- 6b = 168 ( divide both sides by - 6 )

b = - 28

Substitute b = - 28 into (2)

- 8a + 56 = 112 ( subtract 56 from both sides )

- 8a = 56 ( divide both sides by - 8 )

a = - 7

Thus a = - 7 and b = - 28

5 0

3 years ago