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stiks02 [169]
4 years ago
6

A(n) _____ that is perpendicular to a chord bisects the chord.

Mathematics
2 answers:
fgiga [73]4 years ago
6 0

Answer: Radius

Step-by-step explanation: Okay i think its radius but i've been seeing on another question that it was wrong.

Kamila [148]4 years ago
4 0
<span>A__radius___ that is perpendicular to a chord bisects the chord.

answer is 
radius</span>
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<span>hope this helps !

20/((cos(5*x))^2)</span>
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What are the solutions of x^2+6x-6=10
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Answer:

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What’s the answer please
Lunna [17]
You could set up a ratio: 
\frac{186}{3} = \frac{x}{1}
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6 0
4 years ago
Read 2 more answers
ray is buying some ginger roots to brew some fresh ginger ale. The price of the ginger roots is G G, and Ray has a coupon for 1
zalisa [80]

Answer: 0.9 is the decreasing factor.

Step-by-step explanation:

Here,  The price of the ginger roots is G .

And, It there occurs the 10% off on this amount then,

The new price of the ginger is 90% of G.

That is, Final price of G = \frac{90\times G}{100}

= 0.9\times G

= 0.9G

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3 0
3 years ago
Read 2 more answers
Given:
lys-0071 [83]

Answer:

PS=13\text{ units}

Step-by-step explanation:

So, we know that PR is 20, SR is 11, and QS is 5.

We also know that PQ is perpendicular to QR, forming the right angle at ∠Q.

We know all the side lengths except for PQ and PS (the one we want to find). Notice that if we find PQ first, we can then use the Pythagorean Theorem to find PS since we already know QS.

So, let's find PQ.

We can see that we can also use the Pythagorean Theorem on PQ. PQ, QR, and PR (the hypotenuse) will be our sides. So:

(PQ)^2+(QR)^2=(PR)^2

We know that PR is 20.

QR is the combined length of QS+SR, so QR is 5+11 or 16.

So, substitute:

(PQ)^2+(16)^2=(20)^2

Solve for PQ. Square:

(PQ)^2+256=400

Subtract 256 from both sides:

(PQ)^2=144

Take the square root of both sides:

PQ=12

So, the side length of PQ is 12.

Now, we can use the Pythagorean Theorem again to find PS. Notice that PQ, QS, and PS also form a right triangle, with PS being the hypotenuse. So:

(PQ)^2+(QS)^2=(PS)^2

We already know that QS is 5. We also just determined that PQ is 12. Substitute:

(12)^2+(5)^2=(PS)^2

Square:

144+25=(PS)^2

Add:

169=(PS)^2

Take the square root of both sides:

PS=13

Therefore, the length of PS is 13 units.

And we're done!

7 0
4 years ago
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