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romanna [79]
3 years ago
14

Solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 – 6x = 20

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

x^2 – 6x = 20

b=-6

to complete the square, add (b/2)^2 to each side

(b/2)^2 = (-6/2)^2=(-3)^2 =9

x^2 – 6x +9 = 20+9

(x+b/2) ^2 =29

(x-3)^2=29

take the square root of each side

x-3 = +- sqrt (29)

add 3 to each side

x = 3+- sqrt (29)

x = 3 + sqrt(29), x- sqrt(29)

Answer: -2.39, 8.39

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Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In​ addition, there is
Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so P(A) = 0.13.

In​ addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. P(B/A) is the probability that the person is a male, given that he/she jogs. So P(B/A) = 0.156

The Bayes theorem states that:

P(B/A) = \frac{P(A \cap B)}{P(A)}

In which P(A \cap B) is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

So

P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

4 0
4 years ago
A simplified model of the human blood-type system has four blood types: A, B, AB, and O. There are two antigens, anti-A and anti
dexar [7]

Answer: Blood type will be A when event "A" happened and event "B" did not happen. Blood type will be B when event "A" did not happened and event "B" happened. Blood type will be AB when both events happened and blood type will be O when both events did not happen.

Step-by-step explanation:

S={AntiA reacts; AntiA does not react; AntiB reacts; AntiB does not react}

If AntiA reacts and AntiB reacts = AB (A∩B)

If AntiA does not react and AntiB does not react= O (A'∩B')

If AntiA reacts and AntiB does not react= A (A∩B')

If AntiA does not react and AntiB reacts= B (A'∩B)

4 0
3 years ago
Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.
liberstina [14]

Correct answer is A.

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

<h3>How to calculate the diameter?</h3>

If you know the radius of the circle, multiply by 2 to get the diameter. The radius is the distance from the center of the circle to the edge. For example, if the radius of a circle is 4 cm, then the diameter is 4 cm x 2 = 8 cm. If you know the circumference of the circle, divide by π to get the diameter.

<h3>Briefing:</h3>

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction which is A.

The diameter of the circle is used for the square as l=2r therefore corresponds to the diameter, while for a hexagon r=r being the radius of the circle.

To know more about Diameter visit:

brainly.com/question/5501950

#SPJ4

I understand that the question you are looking for is:

Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.

A) The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

B) The radius of the circle is used for the square construction, but the diameter of the circle is used for the regular hexagon construction.

C) The square will need two arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

D) The square will need six arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

7 0
2 years ago
What is (-47/10)-(53/10) is it -3/5 or -10 the calculator says -10 I say -3/5
Rainbow [258]
-\frac{47}{10}-\frac{53}{10}=\\&#10;-\frac{100}{10}=\\&#10;-10
4 0
3 years ago
Read 2 more answers
What is the product of 3x50x18x2? A:1,800 B:5,400 C:540 D:2,700
Delvig [45]

3 x 50 x 18 x 2

3 x 50 = 150

18 x 2 = 36

150 x 36 = 5400

B

8 0
3 years ago
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