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2 years ago

How do you recongnize functions?

Mathematics

2 answers:

natta225 [31]2 years ago

5 0

Answer:

That is not a function :)

Step-by-step explanation:

You can recognize functions by seeing if it passes the vertical line test. If you draw a vertical line anywhere are the grid and it crosses the equation in more then one place then it does not pass the test, and is not a function.

Here's an attachment that might help

kari74 [83]2 years ago

5 0

This graph is not a function.

This is because the line is supposed to touch ONE point on the graph. If the line touches MORE THAN ONE point on the graph it is not considered a function. Hope this helps!

You might be interested in

How do I write each number as a power of the given base? example: 49; base 7

VLD [36.1K]

$7^n=49$
we know that 7*7=49 so thus $7^2=49$
$7^n=7^2$
therefor n=2
it is written as $7^2$

7 0

3 years ago

I need help asap. I don’t know how to do this

irga5000 [103]

Answer:

10 in

Step-by-step explanation:

There are two ways to work this problem, and they give different answers. The reason for that is that the data shown in the diagram is not consistent.

Method 1

Use the area to determine the base length. The area formula is ...

A = (1/2)bh

20 in^2 = (1/2)(b)(4 in)

(20 in^2)/(2 in) = b = 10 in

The missing side dimension is 10 inches.

Method 2

Use the Pythagorean theorem to find the parts of the base, then add them up.

Left of the "?" we have ...

left^2 +4^ = 6^

left^2 = 36 -16 = 20

left = √20 = 2√5

Right of the "?" we have ...

right^2 +4^2 = 8^2

right^2 = 64 -16 = 48

right = √48 = 4√3

So, the base length is ...

base = left + right = 2√5 +4√3

base ≈ 11.400 in

The missing side dimension is 11.4 inches. (The area is 22.8 in^2.)

7 0

3 years ago

Suppose we take the interval [−5,7] and divide it into 4 equal subintervals. Find the width Δn of each subinterval. Δn = If we n

lana66690 [7]

Answer:

$x_0=-5\\x_1=-2\\x_2=1\\x_3=4\\x_4=7$

Δn=3

Step-by-step explanation:

Remember, if we need to divide the interval (a,b) in n equal subinterval, then we need divide the distance (d) between the endpoints of the interval and divide it by n. Then the width Δn of each subinterval is d/n.

We have the interval [-5,7]. The distance between the endpoints of the interval is

$d=7-(-5)=12$ .