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velikii [3]
3 years ago
6

Factor completely 2x2 + 9x + 4.

Mathematics
2 answers:
scZoUnD [109]3 years ago
5 0

Answer:

(2x + 1)(x + 4)

Step-by-step explanation:

2x^2+9x+4

Middle factor split needs to equal 8

2x^2+8x+x+4

2x(x-4)(1(x+4)

(x+4)(2x+1)

Elden [556K]3 years ago
3 0

Answer:

(2x + 4) ( x +1 ) are factors .

Step-by-step explanation:

Given : 2x² + 9x + 4.

To find : Factor.

Solution : We have given that 2x² + 9x + 4.

On factoring 2x² + 8x + 1x + 4.

Taking common 2x from first two terms and 1 from last two terms .

2x ( x +4 ) +1 (x +4 ).

On grouping

(2x + 4) ( x +1 ).

Therefore , (2x + 4) ( x +1 ) are factors .

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Step-by-step explanation:

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Multiply the following rational expressions and simplify the result
GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}

                                   = \frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}

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                                   = \frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}

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