The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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Answer:
41, x=-5
Step-by-step explanation:
m<DEY = m<FEY, by angle bisector theorem
(9x-4) = 41
9x = 45
x = 5
m<DEY = 41
Answer:
7 sheets of paper
Step-by-step explanation:
$40-$19=$21
$21/$3=7 sheets of paper.
In words:
I did 40 minus 19 to get 21, and the divided 21 by 3 to get 7 sheets of paper.
The range of the answer is [-3,infinity) and {yly>=-3}
Area of trapezoid = a + b/2 * h
a = 20, b = 9, h = 21/-16
20+9/2 * (21-16) = 29/2 * 5 = 72.5
The area of the trapezoid = 72.5 in^2
Area of the rectangle = l * w
l = 16, w = 20
16 * 20 = 320
The area of the rectangle: 320 in^2
