Answer:
We have the sentence:
"X by the power of 5 times y to the power of 6 over 2 by the power of -2 times x by the power of 0times x by the power of 9"
Let's break it into parts.
"X by the power of 5 times y to the power of 6..."
This can be written as:
x^5*y^6
"... 2 by the power of -2 times x by the power of 0times x by the power of 9"
This can be written as:
2^(-2)*x^(0)*x^(9)
And we have the quotient between the first thing and the second thing, then the equation is:

And any number by the power of 0 is equal to 1, then:
x^0 = 1, then we can rewrite the equation as:

We can keep simplifying this.
We know that:
a^(-n) = (1/a)^(n)
Then:
2^(-2) = (1/2)^2 = 1/4
Then we get:

And we also know that:
a^n/a^m = a^(n - m)
Then:

And we can't simplify this anymore.
About 1/2 since there is only 2 sides to a coin.
Answer:
3/4 of the fruits were oranges.
Step-by-step explanation:
Answer:
a. 1965
b. 8 years
Step-by-step explanation:
For answers to questions like these it can work to consider the smallest possible dataset.
<h3>Dataset</h3>
For our purpose, consider the 9 years/values to be averaged to be ...
1, 2, 3, 4, 5, 6, 7, 8 ,9
<h3>Observations</h3>
a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.
The first centered value is from the year 1961 +4 = 1965.
b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.
8 years of values are lost.