What are the coordinates of the hole in the rational function? f(x)=x2+8x−9x2−1

1 answer:

4 0

The numerator factored is $(x+9)(x-1)$
The denominator factored is $(x+1)(x-1)$
The x coordinate for the hole comes from the like factor (x - 1).
Set it equal to zero. x - 1 = 0 so x = 1
Plug the x value into the remaining fraction $\frac{x+9}{x+1}$
$\frac{1+9}{1+1} = \frac{10}{2} =5$
The answer is (1,5)

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sineoko [7]

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Step-by-step explanation:

Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation

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