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Oksanka [162]
3 years ago
7

Which element would most likely be a shiny solid at room temperature and have a high density? Kr or Br Cu or F

Chemistry
1 answer:
yuradex [85]3 years ago
6 0
Cu,it would most likely be a shiny solid at room temperature and have high density. •ω•
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Which of the following is most likely to dissolve in NH3? A) CO2 B) CH4 C) H2S D) BH3
dem82 [27]

Answer:

C) H2S

Explanation:

In chemistry, the dissolution of one substance in another is dependent on the magnitude of intermolecular interaction between the two substances.  Hence, if two substances do not interact in one way or the other, then one can not dissolve the other.

Let us consider the fact that NH3 is a polar molecule and it is a general principle that like dissolves like. Hence, only H2S which is also a polar molecule can effectively interact with  NH3 due to dipole-dipole interaction between the two molecules.

Also, ammonia reacts with hydrogen sulphide as follows;

2NH3 + H2S → (NH4)2S

Hence H2S is more likely to dissolve in NH3.

5 0
3 years ago
The decomposition of HBr(g) into elemental species is found to have a rate constant of 4.2 ×10−3atm s−1. If 2.00 atm of HBr are
Dennis_Churaev [7]

Answer:

7,94 minutes

Explanation:

If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>

For the zero-order reactions, concentration-time equation can be written as follows:

                                          [A] = - Kt + [Ao]

where:

  • [A]: concentration of the reactant A at the <em>t </em>time,
  • [A]o: initial concentration of the reactant A,
  • K: rate constant,
  • t: elapsed time of the reaction

<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>

Data:

K = 4.2 ×10−3atm/s,  

[A]o=[HBr]o= 2 atm,  

[A]=[HBr]=0 atm (all HBr(g) is gone)

<em>We clear the incognita :</em>

[A] = - Kt + [Ao]............. Kt =  [Ao] - [A]

                                        t  = ([Ao] - [A])/K

<em>We replace the numerical values:</em>

t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes

So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).

6 0
3 years ago
Morgan wants to compare the weather conditions at her school each day during the week. She decides to measure and record weather
Firlakuza [10]

Answer: Air Temperature

8 0
3 years ago
A 5.5 sample of battery acid contains 490.0g of sulfuric acid H2SO4
prohojiy [21]

n =  \frac{m}{mw}  \\ n =  \frac{490}{98}  \\ n = 5 \: mol
5 0
3 years ago
An element has an atomic number of 29. The number of protons and electrons in a neutral atom of the element are *
nasty-shy [4]

<em>The number of protons and electrons in a neutral atom of the element are;</em>

D. 29 protons and 29 electrons

<u>The atomic number of an element is equal to the number of protons in the nucleus of each atom of that element.</u>

<u>Thus copper has an atomic number of 29, all atoms of copper will have 29 protons.</u>

8 0
2 years ago
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